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2 years ago

Is there gravity in water?

2 answers:

6 0

Gravity works the same way in water that it works in air or a vacuum -- but you have to consider the force of gravity on the water as well as on the object you put into it

Alexus [3.1K]2 years ago

3 0

Answer: Yes.

Explanation:

There is gravity in water because How does the water go up in the cycle? the garavity with the wind pull it up.

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A circular wire loop has a radius of 7.50 cm. a sinusoidal electromagnetic plane wave traveling in air passes throughthe loop, w

ExtremeBDS [4]

Intensity of electromagnetic wave is given as

$I = 2[\frac{B_{rms}^2}{2\mu_0}\times c]$

given that

$I = 0.0275 W/m^2$

$0.0275 = \frac{B_{rms}^2}{\mu_0} \times c$

here we know that

$\mu_0 = 4\pi \times 10^{-7}$

$c = 3 \times 10^8 m/s$

now we have

$0.0275 = \frac{B_{rms}^2}{4 \pi \times 10^{-7}}(3 \times 10^8)$

$B_{rms} = 1.07 \times 10^{-8} T$

now we will have

$B_0 = \sqrt2 B_{rms}$

$B_0 = 1.52 \times 10^{-8} T$

frequency of wave is given as

$f = \frac{c}{\lambda}$

$f = \frac{3 \times 10^8}{6.90} = 4.35 \times 10^7 Hz$

now the induced EMF is given as

$EMF = B_0A2\pi f$

$EMF = 1.52 \times 10^{-8} \times \pi(0.075)^2 \times (2\pi \times 4.25 \times 10^7)$

$EMF = 0.0733 Volts$

7 0

3 years ago

Read 2 more answers

A student says that a speed of 50 m/s is faster than a speed of 140 km/h because the number is bigger. What would you say to the

Yuri [45]

if you convert these into miles per hour 50 m/s would be higher, since

50 m/s = 111.85 mph and

140 km/h = 86.99 mph

3 0

3 years ago

Select the volume units that are greater than one liter.

Andreas93 [3]

A.) kiloliter. 1 kiloliter = 1,000 liters
c.) megaliter. 1 megaliter = 1,000,000 liters

hope this helps

5 0

2 years ago

Read 2 more answers

A system undergoes a two-step process. In the first step, the internal energy of the system increases by 222 J when 150 J of wor

joja [24]

Answer:0 J

Explanation:

Given

For first step

change in internal Energy of the system is $\Delta U_1=222 J$

Work done on the system $W_1=-150 J$

For second step

change in internal Energy of the system is $\Delta U_2=123 J$

Work done on the system $W_2=-195 J$

Work done on the system is considered as Positive and vice-versa.

and from first law of thermodynamics

$Q=\Delta U+W$

for first step

$Q_1=222-150=72 J$

$Q_2=123-195=-72 J$

overall heat added $=Q_1+Q_2$

$Q_{net}=72-72 =0$

For overall Process Heat added is 0 J

8 0

2 years ago

Two protons are maintained at a separation of nm. Calculate the electric potential due to the two particles at the midpoint betw

Liono4ka [1.6K]

Answer:

The electric potential is approximately 5.8 V

The resulting direction of the electric field will lie on the line that joins the charges but since it is calculated in the midpoint and the charges are the same we can directly say that its magnitude is zero

Explanation:

The two protons can be considered as point charges. Therefore, the electric potential is given by the point charge potential:

$\displaystyle{U=\frac{q}{4\pi \epsilon_0r}}$ (1)

where $q$ is the charge of the particle, $\epsilon_0$ the electric permittivity of the vacuum (I assuming the two protons are in a vacuum) and $r$ is the distance from the point charge to the point where the potential is being measured. Because the electric potential is an scalar, we can simply add the contribution of the two potentials in the midpoint between the protons. Thus:

$\displaystyle{U_{midpoint}=\frac{q}{4\pi \epsilon_0r}}+\frac{q}{4\pi \epsilon_0r}}=\frac{q}{2\pi \epsilon_0r}}}$

Substituting the values $q=1.602 \cdot10^{-19}\ C$ , $\displaystyle{\frac{1}{4\pi\epsilon_0}=8.99\cdot 10^9 N\cdot m^2\cdot C^{-2}}$ and $r=0.5 \cdot 10^{-9} m$ we obtain:

$\displaystyle{U_{midpoint}=\frac{q}{2\pi \epsilon_0r}}=5.759 \approx 5.8 V}$

6 0

3 years ago