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Andrej [43]
3 years ago
5

Water is flowing through a pipe whose cross sectional area at point A is larger than the cross sectional area at point B. The re

ading on a pressure gauge connected to the pipe at point A will be lower than the reading on a pressure gauge connected to the pipe at point B.
a.True
b.False
Physics
1 answer:
Tcecarenko [31]3 years ago
5 0

Answer:

a. True

Explanation:

Pressure is always inversely proportional to the cross section area

This can be proven from the equation P = F/A

Where P = Pressure, F = Force and A = Cross-sectional area

This can also be similarly proven from the continuity equation given as

A₁V₁ = A₂V₂

Where A₁ = Area in first part of pipe (point A)

A₂ = Area in second part of pipe (point B)

V₁ = Velocity of water in first part of pipe (point A)

V₂ = Velocity of water in second part of pipe (point B)

From the continuity equation we can have that

V₁/V₂ = A₂/A₁

Thus the velocity of the liquid at any point in the pipe is inversely proportional to the cross-sectional area of the pipe. The liquid will be moving  slowly where the area is large and will be moving rapidly where the area  is small, and since the velocity is directly proportional to the force (F = m × v/t)which id in turn directly proportional to the pressure (P = F/A), this proves my answer to be True!

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Which of these common substances is a heterogeneous mixture?
LenaWriter [7]

Answer:

<em>(C) If the composition of a mixture appears uniform no matter where you sample it, is homogeneous; sand on a beach *IS HETEROGENEOUS* because when you look at it up close, you can identify different types of particles, such as sand, shells, and organic matter.</em>

Explanation:

<em>(A) Pure Water is a collection of solely H2O molecules therefore Pure Water is classified as a *Compound*.</em>

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<em>-Hope this helps!</em>

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4 0
3 years ago
Which item could you use in place of an ammeter to demonstrate that a
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Explanation:

6 0
2 years ago
Which process is represented by the PV diagram shown below?
MrMuchimi

Answer: B. the isovolumetric process

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<em>Hence, option B is the correct answer.</em>

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8 0
3 years ago
A JFET has a drain current of 5mA. If IDSS = 10mA and VGS ( off )= -6 v. find The Value Of
levacccp [35]

\underline {\huge \boxed{ \sf \color{skyblue}Answer :  }}

<u>Given :</u>

\tt \large {\color{purple}     ↬ }  \:  \:  \:  \:  \:  I_{D} = 5mA

\:  \:

\tt \large {\color{purple}     ↬ }  \:  \:  \:  \:  \:  I_{DSS} = 10mA

\:  \:

\tt \large {\color{purple}     ↬ }  \:  \:  \:  \:  \:  V_{GS(off)} = -6V

\:  \:

\tt \large {\color{purple}     ↬ }  \:  \:  \:  \:  \:  V_{GS} =   {?}

\:  \:  \:

<u>Let's Slove :</u><u> </u>

  • \tt \large  I_{D} = I_{(DSS)}  (1 -   \frac {V_{GS}}{V_{GS(off)}} )^{2}

\:  \:  \:

  • \tt \large \: V_{GS} = (1 -  \frac{ \sqrt{I_D} }{ \sqrt{I_{DSS}} } ) \times  V_{GS(off)}

\:  \:  \:

  • \tt \large \: V_{GS} = (1 -  \frac{ \sqrt{5m} }{ \sqrt{10m} } ) \times  { - 6}

\:  \:

  • \underline \color{red} {\tt \large \boxed {\tt V_{GS} = 1.75 ✓}}
3 0
1 year ago
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