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3 years ago

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If you are in motion can you have the same speed as someone else in motion but different velocities? Give an example

1 answer:

geniusboy [140]3 years ago

7 0

Answer:

Yes

Explanation:

Velocity is a vector quantity, meaning it has size and direction, as opposed to speed, a scalar quantity which only has size.

An example is speed may be 30km/h, and an example of velocity is 30km/h East.

Therefore two people can have the same speed and different velocities because they can be traveling in different directions.

For example, you and your friend could be doing shuttles together but you started at one wall and they started at the other, so even though you are running at the same speed, you always have different velocities because they are running in the opposite direction as you.

Hope this helped!

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Two particles each of mass m and charge q are suspended by strings of length / from a common point. Find the angle e that each s

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Answer:

$\theta =\left (\frac{kq^{2}}{4L^{2}\times mg} \right )^{\frac{1}{3}}$

Explanation:

Let the length of the string is L.

Let T be the tension in the string.

Resolve the components of T.

As the charge q is in equilibrium.

T Sinθ = Fe ..... (1)

T Cosθ = mg .......(2)

Divide equation (1) by equation (2), we get

tan θ = Fe / mg

$tan\theta =\frac{\frac{kq^{2}}{AB^{2}}}{mg}$

$tan\theta =\frac{\frac{kq^{2}}{4L^{2}Sin^{\theta }}}}{mg}$

$tan\theta =\frac{kq^{2}}{4L^{2}Sin^{2}\theta \times mg}$

$tan\theta\times Sin^{2}\theta =\frac{kq^{2}}{4L^{2}\times mg}$

As θ is very small, so tanθ and Sinθ is equal to θ.

$\theta ^{3} =\frac{kq^{2}}{4L^{2}\times mg}$

$\theta =\left (\frac{kq^{2}}{4L^{2}\times mg} \right )^{\frac{1}{3}}$

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A space probe produces a radio signal pulse. If the pulse reaches Earth 12.3 seconds after it is emitted by the probe, what is t

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Answer:

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Distance = speed × time .....1

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Speed of radio signal = speed of light = 3.0 × 10^8 m/s

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Substituting the values of speed and time into equation 1;

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