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hram777 [196]
3 years ago
9

If you are in motion can you have the same speed as someone else in motion but different velocities? Give an example

Physics
1 answer:
geniusboy [140]3 years ago
7 0

Answer:

Yes

Explanation:

Velocity is a vector quantity, meaning it has size and direction, as opposed to speed, a scalar quantity which only has size.

An example is speed may be 30km/h, and an example of velocity is 30km/h East.

Therefore two people can have the same speed and different velocities because they can be traveling in different directions.

For example, you and your friend could be doing shuttles together but you started at one wall and they started at the other, so even though you are running at the same speed, you always have different velocities because they are running in the opposite direction as you.

Hope this helped!

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A parallel-plate capacitor is charged and then is disconnected from the battery. By what factor does the stored energy change wh
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Answer:

0.5

Explanation:

The energy of a charged capacitor is given by \frac{1}{2}QC where Q is the charge on it and C is its capacitance. The capacitance is defined, geometrically, as

\dfrac{\epsilon A}{d}

where \epsilon is a constant that is determined by the material between the plates, A is the area of the plates and d is the distance between them. It is then that the capacitance is linearly inversely proportional to the separation distance; as the distance increases, the capacitance reduces.

Because it is linear, when the separation distance is doubled, other factors remaining constant, the capacitance is halved. Because the capacitance is halved, the energy is halved.

Let's see the mathematics.

Initial capacitance, C_1 at initial separation, d_1

C_1=\dfrac{\epsilon A}{d_1}

If separation is doubled, separation becomes d_2=2d_1. Then the capacitance becomes

C_2=\dfrac{\epsilon A}{d_2}

C_2=\dfrac{\epsilon A}{2d_1}

C_2=0.5\dfrac{\epsilon A}{d_1}

C_2=0.5C_1

Initial energy, E_1=\frac{1}{2}QC_1

Final energy, E_2=\frac{1}{2}QC_2= \frac{1}{2}Q\times0.5C_1

E_2=0.5\times\frac{1}{2}QC_1=0.5E_1

Hence, \frac{E_2}{E_1}=0.5

5 0
3 years ago
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