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attashe74 [19]
3 years ago
7

Un numero entero es un numero impar si y solo si no es divisible por 2

Mathematics
1 answer:
meriva3 years ago
8 0
Si, es cierto. Si, es cierto.
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What number 1,2,3? Im a lil confused:/
max2010maxim [7]
Undo the X first...........
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3 years ago
Use the x-intercept method to find all real solutions of the equation.<br> x^3-8x^2+9x+18=0
meriva

Answer:

a. x=-1,3,\:or\:6

Step-by-step explanation:

The given equation is;

x^3-8x^2+9x+18=0

To solve by the x-intercept method we need to graph the corresponding function using a graphing calculator or software.

The corresponding function is

f(x)=x^3-8x^2+9x+18

The solution to x^3-8x^2+9x+18=0 is where the graph touches the x-axis.

We can see from the graph  that; the x-intercepts are;

(-1,0),(3,0) and (6,0).

Therefore the real solutions are:

x=-1,3,\:or\:6

8 0
4 years ago
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It’s two parts help me
ehidna [41]

Answer:

40 degree acute

Step-by-step explanation:

8 0
3 years ago
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Question 5 (1 point)
ElenaW [278]

Answer:

The volume of the shape is 560 ft^3

Step-by-step explanation:

To find the volume of the figure, we need to multiply the base area by the height of the figure

mathematically, we have the base area as a rectangular shape and its area is the product of its side lengths

We have this as 8 ft * 10 ft = 80 ft^2

So multiplying this by the height which is 7 ft, we have this as;

7 ft * 80 ft^2 = 560 ft^3

3 0
3 years ago
(1 point) Linear System - Three Variables Solve the following system of equations using Gaussian elimination method. If there ar
EastWind [94]

Answer:

x=\frac{-363}{70} ≈ -5.1857

y=\frac{-192}{35} ≈ -5.4857

z=\frac{313}{84} ≈ 3.7262

Step-by-step explanation:

Rewrite the equation system as:

6x+8y=-75

-3x+6y+6z=5

2x-9y=39

Now, write the system in its augmented matrix form:

\left[\begin{array}{cccc}6&8&0&-75\\-3&6&6&5\\2&-9&0&39\end{array}\right]

applying row reduction process to  its associated augmented matrix:

Swap R1 and R3, and then Swap R1 and R2:

\left[\begin{array}{cccc}-3&6&6&5\\2&-9&0&39\\6&8&0&-75\end{array}\right]

R3+2R1

\left[\begin{array}{cccc}-3&6&6&5\\2&-9&0&39\\0&20&12&-65\end{array}\right]

3R2+2R1

\left[\begin{array}{cccc}-3&6&6&5\\0&-15&12&127\\0&20&12&-65\end{array}\right]

15R3+20R2

\left[\begin{array}{cccc}-3&6&6&5\\0&-15&12&127\\0&0&420&1565\end{array}\right]

Now we have a simplified system:

-3x+6y+6z=5\\0-15y+12z=127\\0+0+420z=1565

-3x+6y+6z=5\hspace{5 mm}(1)\\0-15y+12z=127\hspace{3 mm}(2)\\0+0+420z=1565\hspace{3 mm}(3)

From (3):

z=\frac{313}{84} (4)

Replacing (4) in (2)

y=\frac{-192}{35} (5)

Finally replacing (5) and (4) in (1)

x=\frac{-363}{70}

7 0
3 years ago
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