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nasty-shy [4]
3 years ago
14

What is the answer for this inequality " |2k+1|>5

Mathematics
1 answer:
TiliK225 [7]3 years ago
6 0
2k+1>5 and 2k+1<-5
2k>4 2k<-6
k>2 k<-3
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(1 point) If p(x) and (x) are arbitrary polynomials of degree at most 2, then the mapping =p(-1)q(-1) + p(070) +p(3)q(3) defines
Ainat [17]

If p(x) and q(x) are arbitrary polynomials of degree at most 2 then

||p||||q|| = 26(\sqrt{640}) and angle between p(x) and q(x) is 0.233.

Given that

<p,q> = p(-1)q(-1) + p(0) q(0) + p(3)q(3)

and p(x) = 2x²+ 6 , q(x)= 4x²-4x

then the values of p and q at x = -1,0,3 are given as;

x = -1,

p(-1) = 2(-1)² + 6 = 8   ,    q(-1) = 4(-1)² - 4(-1) = 8

x = 0,

p(0) = 2(0)² + 6 = 6   ,    q(0) = 4(0)² - 4(0) = 0

x = 3,

p(3) = 2(3)² + 6 = 24  ,  q(3) = 4(3)²- 4(3) = 24.

<p,q> = p(-1)q(-1) + p(0)q(0) + p(3)q(3)

         = (8)(8) + (6)(0) + 24(24)

         = 64 + 0 + 576

<p,q> = 640

Now we have to find ||p|| ||q||, for this we'll find ||p|| and ||q||

||p|| = \sqrt{ < p,p > }

     = \sqrt{8(8) + 6(6) + 24(24)}

     = \sqrt{676}

||p|| = 26

and

||q|| = \sqrt{ < q,q > }

      =\sqrt{8(8) + 0(0) + 24(24)}

||q||  =\sqrt{640}

∴||p||||q|| = 26(\sqrt{640\\)

Now we have to find angle between p(x) and q(x),

∴ α = cos⁻¹\frac{ < p,q > }{||p||||q||}

      = cos ⁻¹ \frac{640}{26(\sqrt{640}) }

      = cos ⁻¹ \frac{4\sqrt{10} }{13}

  α  = 13.34°

In radian

α = 0.233.

To know more about Inner product here

brainly.com/question/14185022

#SPJ4

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1 year ago
What is the output, or dependent variable of quantity?<br><br> 1: x<br> 2:f(x)<br> 3:y
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The answer would be y
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4 years ago
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3x2 + 2(x2 – 20) = 16 - 2x2
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3x(2) + 2(2x - 20) = 16 - 2x(2)

6x + 4x - 40 = 16 - 4x

10x - 40 = 16 - 4x

14x - 40 = 16

14x = 56

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Hope this helps! ;)

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3 years ago
You run one lap around a mile track every eight minutes you're friend runs around the same track every 10 minutes. You both star
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10 , 20 , 30 , 40 , 50
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PLEASE HELP!!!!!!
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