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DedPeter [7]
4 years ago
10

What is true about a circular orbit?

Physics
1 answer:
emmasim [6.3K]4 years ago
6 0
A circle is just a very very very special kind of ellipse.
So the correct choice is ' A ' .
You might be interested in
The geologic force applied to rocks is called
amid [387]
The geologic force applied to rocks is called compression. Compression<span> is the stress that squeezes </span>rocks<span> together. As a result of the c</span>ompression rocks fold or fracture depending on their compressive strength<span> or </span>compression strength<span> - the capacity of a material or structure to withstand loads tending to reduce size.
</span>When the compression is horizontal the crust will be s<span>hortened and thickened.</span><span> When the compression is vertical maximum a section of rock will fail in </span>normal faults<span>, horizontally extending and vertically thinning a given layer of rock.</span>
4 0
3 years ago
A meter stick is balanced at the 50 cm mark. You tie a 20 N weight at the 20 cm mark. Where should a 30 N weight be placed so th
vivado [14]

Answer:

20 cm to the right of the center or 20+50 = 70 cm from the left side.

Explanation:

The length of meter stick is 1 m = 100 cm

Balance point on 50 cm

From the center the 20 N weight is 50-20 = 30 cm

Torque is obtained when force is multiplied with the distance

As the force is conserved we have

\dfrac{20}{30}\times 30=20\ cm

The distance will be 20 cm to the right of the center or 20+50 = 70 cm from the left side.

7 0
3 years ago
A 4.4-µF capacitor is initially connected to a 5.1-V battery. Once the capacitor is fully charged the battery is removed and a 2
Grace [21]

Question is incomplete. Missing part:

Find the charge on the capacitor at the following times:

1) t = 0 mu S  

2) t = 1 mu S

3) t = 50 mu S

1) 22.4 \mu C

We start by calculating the initial charge on the capacitor. For this, we can use the following relationship:

C=\frac{Q_0}{V_0}

where

C is the capacitance

Q0 is the initial charge stored

V0 is the initial potential difference across the capacitor

When the capacitor is connected to the battery, we have:

C=4.4\mu F = 4.4\cdot 10^{-6}F

V_0 = 5.1 V

Solving for Q_0,

Q_0 = CV_0 = (4.4\cdot 10^{-6})(5.1)=2.24 \cdot 10^{-5} C = 22.4 \mu C

So, when the battery is disconnected, this is the charge on the capacitor at time t = 0.

2) 20.0\mu C

To find the charge on the capacitor at any other time t, we use the equation:

Q(t) = Q_0 e^{-\frac{t}{RC}}

where

Q_0 = 22.4 \mu C

t is the time

R=2.0 \Omega is the resistance

C=4.4\mu F is the capacitance

Therefore, at time t=1 \mu s, we have:

Q(t) = (22.4) e^{-\frac{1}{(2.0)(4.4)}}=20.0 \mu C

3) 0.08 \mu C

As before, we use again the equation:

Q(t) = Q_0 e^{-\frac{t}{RC}}

However, here the time to consider is

t=50 \mu C

Substituting into the formula,

Q(t) = (22.4) e^{-\frac{50.0}{(2.0)(4.4)}}=0.08 \mu C

4 0
3 years ago
12 POINTS PLUS MARKF BRAINILEST
Usimov [2.4K]

Answer:

gas

Explanation:

7 0
4 years ago
Read 2 more answers
If you increase the mass but leave the volume the same what happens to the density of the object
atroni [7]
Density is a property of an object or substance that can be described through the correlation of the mass of an object over its volume.

Mathematically, density = mass / volume.
In description, the relationship of density and mass is positively correlated and with volume, inversely.
Since density and mass is positively correlated then if you increase the mass, the density of the object will also increase leaving density and volume the same.

Example:
Mass = 10 g changes to 20
Volume = 5 cm3
Density =?

1. D = m / v
2. D = 10 g / 5 cm3
3. D = 2 g / cm3
4. D = 20 g / 5 cm3
5. D = 4g/cm3



3 0
3 years ago
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