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4 years ago

When is the tide the highest

Physics

2 answers:

kati45 [8]4 years ago

6 0

When the moon is between the sun and the earth.

Deffense [45]4 years ago

6 0

-- the Earth is at perihelion (around January 5)
and
-- the Moon is at perigee (once every 27.32 days)

and

either
-- the Moon is New (once every 29.53 days)
or
-- the Moon is Full (once every 29.53 days)

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Suppose a diving board with no one on it bounces up and down in a simple harmonic motion with a frequency of 6.90 Hz. The board

Kobotan [32]

Answer:

The frequency of the simple harmonic motion of a 67.6 kg diver on the board = 2.48 Hz

Explanation:

The frequency in simple harmonic motion is related to spring constant and mass causing the motion through the relation

f = (1/2π) √(k/m)

When mass = 10 kg, f = 6.90 Hz,

6.9 = (1/2π) √(k/10)

(√(k/10) = 6.9×2π = 43.354

k/10 = 43.354² = 1879.57

K = 18795.7 N/m

When a diver of mass 67 kg climbs the diving board, the total mass on the diving board now becomes (10+67.6) = 77.6 kg

Spring constant of the diving board doesn't change,

So, the frequency is then given by

f = (1/2π) √(18795.7/77.6)

f = 2.48 Hz

8 0

3 years ago

Read 2 more answers

Plate Tectonics Lab: Snicker’s Science

Marizza181 [45]

Answer:

sup

Explanation:

8 0

3 years ago

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Earth is slightly closer to the sun in january than in july. How does the area swept out by earth’s orbit around the sun during

Anna007 [38]

This is because both areas are the same.

8 0

3 years ago

The part of the atom that accounts for electricity is the

hichkok12 [17]

<span>The part of the atom that accounts for electricity is the "Electron"

In short, Your Answer would be Option A

Hope this helps!</span>

4 0

3 years ago

Read 2 more answers

Two satellites A and B orbit the Earth in the same plane. Their masses are 5 m and 7 m, respectively, and their radii 4 r and 7

Dmitry [639]

Answer:

The ratio of their orbital speeds are 5:4.

Explanation:

Given that,

Mass of A = 5 m

Mass of B = 7 m

Radius of A = 4 r

Radius of B = 7 r

The orbital speed of satellite A,

$v_{A}=\sqrt{\dfrac{GM_{A}}{R_{A}}}$ ......(I)

The orbital speed of satellite B,

$v_{B}=\sqrt{\dfrac{GM_{B}}{R_{B}}}$ ......(I)

We need to calculate the ratio of their orbital speeds

Using equation (I) and (II)

$\dfrac{v_{A}}{v_{B}}=\sqrt{\dfrac{\dfrac{GM_{A}}{R_{A}}}{\dfrac{GM_{B}}{R_{B}}}}$

Put the value into the formula

$\dfrac{v_{A}}{v_{B}}=\sqrt{\dfrac{G\times5m\times7r}{G\times7m\times4r}}$

$\dfrac{v_{A}}{v_{B}}=\dfrac{5}{4}$

Hence, The ratio of their orbital speeds are 5:4.

8 0

3 years ago