The provided question has marked options incorrectely the correct order as follows:
A) Expose putative DNA repair mutant plants to ionizing radiation L and see if they survive less well than wild-type plants.
B) Measure the amount of post-translational processing that occurs in the putative DNA repair mutant plants.
C) Measure the somatic mutation rates for the putative DNA repair mutant plants.
D) Expose the putative DNA repair mutant plants to a deaminating agent and select those that have a decreased mutation rate.
E) Measure the germline spontaneous and induced mutation rates for the putative DNA repair mutant plants.
Answer:
The correct answer is: A), C) and E)
Explanation:
The breeder wants to isolate the mutants in tomatoes that are defective in DNA repair, to identify such plants breeder should follow these methods as they will allow best to identifying the defective tomatoes-
Measure the somatic mutation rates for the putative DNA repair mutant plants.
Measure the germline spontaneous and induced mutation rates for the putative DNA repair mutant plants.
Expose putative DNA repair mutant plants to ionizing radiation L and see if they survive less well than wild-type plants. This will allow the breeder to see and analyze the ability of DNA repair in tomatoes
Answer:
B) Binocular stereoscopic vision, grasping hands and feet, and nails on the toes and fingers all co-evolved to enhance visual predation on insects in the terminal branches of trees.
Explanation:
A characteristic of the primates, when they evolved was the replacement of the claws by ones, the binocular vision, which generated these two characteristics the option to see and take better the insects and fruit in high branches
Answer:
Bacteria, but out of those three then it would be land, because animals (dinosaurs) Could not live without food (plants) and plants can't grow without land.
Explanation:
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cellulose is a polysaccharide.
A significant class of biomolecules is polysaccharides. They are large chains of monosaccharide molecules that are linked together. These intricate biomacromolecules serve as a vital energy source for animal cells and are a crucial part of plant cells' structural makeup. The nature of the monosaccharides determines whether it is a homopolysaccharide or a heteropolysaccharide.
A branching polysaccharide is a type of carbohydrate that is different from a linear polysaccharide, which is a straight chain of monosaccharides.
Organisms have this energy in reserve. The molecules are hydrophobic because water cannot enter them because of the many hydrogen bonds present. They permit adjustments to the concentration gradient, which affects how the cells absorb nutrients and water.
Learn more about Polysaccharide here:
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Answer:
Bacteria are single-celled organisms that live in different environments, including cold and hot, and they can also live on or inside the human body.
Most types of bacteria are harmless, on the contrary, they help in the process of digesting food, attacking other microbes and fighting cancer cells, and less than 1% of bacteria are bacteria that cause diseases.
As for viruses, they are very small organisms, smaller than bacteria, consisting of DNA and a protein that coat them, and unlike bacteria, a virus does not reproduce without its presence in the cells of living organisms.
