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Stolb23 [73]
3 years ago
15

Calculate the percent composition of NaNO3

Chemistry
1 answer:
Ivanshal [37]3 years ago
6 0

Answer:

27.05% Na

16.48% N

56.47% O

Explanation:

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You wish to make 250. mL of 0.20 M KCl from a stock solution of 1.5 M KCl and DI water.
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The question requires us to use the dilution formula M_iV_i=M_fV_f, where M_i and V_i are the stock concentration and volume respectively, then M_f and V_f are the dilute concentration and volume respectively.

a. C_s_t_o_c_k= 1.5 M KCI, C_d_i_l_u_t_e=0.20M KCl, V_d_i_l_u_t_e=250ml KCl

b.M_iV_i=M_fV_f\\\implies V_i= \frac{M_fV_f}{M_i} = \frac{0.20M \times 250ml}{1.5M} = 33.3\ ml

To prepare the solution 33.3ml of 1.5M KCl is diluted to a total final volume of 250ml.


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