Answer:
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Explanation:
I makes sense to pick option 2
Answer: The molar concentration of acetic acid in the vinegar is 0.539 M.
Explanation:
The formula used is:
where,
and are the concentration and volume of base.
and are the concentration and volume of an acid.
Given:
Molar concentration of NaOH = 0.1798 M
Volume of NaOH = 30.01 mL
Volume of acetic acid = 10.0 mL
Now putting all the given values in the above formula, we get:
Thu, the molar concentration of acetic acid in the vinegar is 0.539 M.
CH₄ + 2O₂ ---> CO₂ + 2H₂O
16g..................................18g×2
16g CH₄ --- 36g H₂O
5,1g CH₄ --- X
X = (5,1×36)/16
X = 11,475g H₂O
a) Mg is oxidized and O2 is reduced
b) Zn is oxidized while Pb(NO3)2 is reduced.
<h3>Oxidation and reduction</h3>
Oxidation is defined as:
- loss of electrons
- removal of hydrogen
- addition of oxygen
- increase in oxidation number
- removal of electropositive elements
Reduction is defined as:
- gains of electrons
- addition of hydrogen
- removal of oxygen
- decrease in oxidation number
- addition of electropositive elements
Looking at the first reaction, the Mg atom gains oxygen to become MgO. This means that Mg is oxidized. The oxidizing agent is O2. At the same time, O2 is being reduced and the reducing agent is Mg.
For the second reaction, the oxidation number of Pb is reduced from +2 to 0. Thus, Pb has been reduced by Zn while Zn itself has been oxidized. The reducing agent here is Zn while the oxidizing agent is Pb(NO3)2.
More on oxidation and reduction can be found here: brainly.com/question/13699873
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Answer:
28.45L
Explanation:
1mole of a gas occupy 22.4L at stp. This implies that 1mole of He also occupy 22.4L at stp.
Now if 1mole of He occupied 22.4L at stp, then, 1.27mol will occupy = 1.27x22.4 = 28.45L