Answer:
are usually multicellular
contain a true nucleus
contain membrane-bound organelles
Explanation:
Answer:
678 mL.
Explanation:
The balanced reaction between calcium chloride and silver nitrate is shown in figure.
As shown in the equation , each mole of aqueous calcium chloride will rect with two moles of silver nitrate.
The moles of calcium chloride taken = molarity X volume (L)
= 0.37X0.33 = 0.122 mol
the moles of silver nitrate required = 2 X 0.122 = 0.244 mol
the volume of silver chloride required =
M = 0.36 M
mol = 0.244
Putting values
volume = 0.678 L = 678 mL.
Answer:
→
Explanation:
→
On the left you have:
Na: 1
Br: 2
On the right you have:
Na: 1
Br: 1
To get the Br to be the same on both sides, you would multiple the NaBr by 2. Then, you will have 2 Na so you put a coefficient of 2 in front of the Na aswell.
Answer:
Explanation:
We know,
where, R = 0.0821 L.atm/(mol.K), T is temperature in kelvin and is difference in sum of stoichiometric coefficient of products and reactants
Here and T = 311 K
So,
Hence value of equilibrium constant in terms of partial pressure is
Answer:
Fe(iii)2O3 + 3CO ===> 2Fe + 3CO2
Explanation:
Fe(iii)2O3 + CO ===> Fe + CO2
The best thing to do is start with the Oxygens. They are the most complicated.
Fe(iii)2O3 + 3 CO ===> Fe + 3 CO2
Unfortunately this equation is a bit of by guess and by gosh. You need to balance the oxygens so that the total is an even number. That's because the right hand side is always going to be even. [The 2 on CO2 will make anything in front of it even).
So there are 6 oxygens on the left and 6 on the right. The carbons by accident are balanced with this maneuver. So all that is left is the irons.
Fe(iii)2O3 + 3CO ===> 2Fe + 3CO2
This equation is a bit nasty, but in higher chemistry courses, you will learn how to make it a whole lot simpler. For now you are just going to have to put up with the nastiness of the question and guess.