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Bezzdna [24]
3 years ago
7

Calculate the mass of water formed from the complete combustion of 5.10 g of methane, ch4, in the reaction ch4 (g) + 2 o2 (g) --

> co2 (g) + 2 h2o (g).
Chemistry
1 answer:
Anton [14]3 years ago
4 0
CH₄ + 2O₂ ---> CO₂ + 2H₂O
16g..................................18g×2

16g CH₄ --- 36g H₂O
5,1g CH₄ --- X
X = (5,1×36)/16
X = 11,475g H₂O
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Answer:

Diamond.

Explanation:

Having thermal conductivity of more than 2,000 WMK

WMK = Watts per Meter per Kelvin

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What are the steps to go from the names of compounds to the formulas
marysya [2.9K]

Answer:

Explanation:

write down the formulas, use the expressions and formulas to convert

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2 years ago
Describe what half-life is.<br> answer in a paragraph please.
dangina [55]

Half-life is defined as the quantity to reduce to half of its initial value.

Explanation:

The term half-life is generally used in nuclear physics which describes how long a stable atom can survive a radioactive decay or how quickly an unstable stable atom can undergo radioactive decay. Half-life is a constant and does not have any units.

<u>The formula to calculate half-life: </u>

N(t) = \bold{N_{0} e^{-\lambda t}}

Here N(t) is the quantity which is “not decayed”.

N_0 is the “initial quantity” of the substance.

λ is the “decay constant”

4 0
3 years ago
9.69×10^25 formula units of iron(III) nitrate is equal to how many moles of Fe(NO3)3?
scoray [572]

Answer:

160.9 mol ≅ 161.0 mol.

Explanation:

  • It is known that every 1.0 mole of compound or element contains Avogadro's number (6.022 x 10²³) of molecules or atoms (formula units).

Using cross multiplication:

1.0 mole of Fe(NO₃)₃ contains → 6.022 x 10²³ formula units.

??? mole of Fe(NO₃)₃ contains → 9.69 x 10²⁵ formula units.

<em>∴ The no. of moles of He contains (9.69 x 10²⁵ formula units)</em> = (1.0 mol)(9.69 x 10²⁵ formula units.)/(6.022 x 10²³ formula units) = <em>160.9 mol ≅ 161.0 mol.</em>

6 0
3 years ago
What is the vapor pressure at 20 °c of an ideal solution prepared by the addition of 7.38 g of the nonvolatile solute urea, co(n
Romashka [77]

Answer:

83.24 mmHg.

Explanation:

  • <em>The vapor pressure of the solution (Psolution) = (Xmethanol)(P°methanol).</em>

where, Psolution is the vapor pressure of the solution,

Xmethanol is the mole fraction of methanol,

P°methanol is the pure vapor pressure of methanol.

  • We need to calculate the mole fraction of methanol (Xmethanol).

<em>Xmethanol = (n)methanol/(n) total.</em>

where, n methanol is the no. of moles of methanol.

n total is the total no. of moles of methanol and urea.

  • We can calculate the no. of moles of both methanol and urea using the relation: n = mass/molar mass.

n of methanol = mass/molar mass = (56.9 g)/(32.04 g/mol) = 1.776 mol.

n of urea = mass/molar mass = (7.38 g )/(60.06 g/mol) = 0.123 mol.

∴ Xmethanol = (n)methanol/(n) total = (1.776 mol)/(1.776 mol + 0.123 mol) = 0.935.

<em>∴ Psolution = (Xmethanol)(P°methanol)</em> = (0.935)(89.0 mmHg) =<em> 83.24 mmHg.</em>

7 0
2 years ago
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