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Bezzdna [24]
3 years ago
7

Calculate the mass of water formed from the complete combustion of 5.10 g of methane, ch4, in the reaction ch4 (g) + 2 o2 (g) --

> co2 (g) + 2 h2o (g).
Chemistry
1 answer:
Anton [14]3 years ago
4 0
CH₄ + 2O₂ ---> CO₂ + 2H₂O
16g..................................18g×2

16g CH₄ --- 36g H₂O
5,1g CH₄ --- X
X = (5,1×36)/16
X = 11,475g H₂O
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Stoichiomety:

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multiply each # of moles times the atomic molar mass of the compund to find the relation is weights

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May be they just pretended that you use the law of consrvation of mass and say that you need 72 g - 18g = 54 g. But it violates the proportion of C and O2 in the CO2 and is not possible.
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