Calculate the mass of water formed from the complete combustion of 5.10 g of methane, ch4, in the reaction ch4 (g) + 2 o2 (g) --
> co2 (g) + 2 h2o (g).
1 answer:
CH₄ + 2O₂ ---> CO₂ + 2H₂O
16g..................................18g×2
16g CH₄ --- 36g H₂O
5,1g CH₄ --- X
X = (5,1×36)/16
X = 11,475g H₂O
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