5.4 M = moles of solute / 1.50 L
<span>Multiply both sides by 1.50 L to isolate moles of solute on the right. </span>
<span>8.1 mol = moles of solute </span>
Answer:
The lock-and-key model:
c. Enzyme active site has a rigid structure complementary
The induced-fit model:
a. Enzyme conformation changes when it binds the substrate so the active site fits the substrate.
Common to both The lock-and-key model and The induced-fit model:
b. Substrate binds to the enzyme at the active site, forming an enzyme-substrate complex.
d. Substrate binds to the enzyme through non-covalent interactions
Explanation:
Generally, the catalytic power of enzymes are due to transient covalent bonds formed between an enzyme's catalytic functional group and a substrate as well as non-covalent interactions between substrate and enzyme which lowers the activation energy of the reaction. This applies to both the lock-and-key model as well as induced-fit mode of enzyme catalysis.
The lock and key model of enzyme catalysis and specificity proposes that enzymes are structurally complementary to their substrates such that they fit like a lock and key. This complementary nature of the enzyme and its substrates ensures that only a substrate that is complementary to the enzyme's active site can bind to it for catalysis to proceed. this is known as the specificity of an enzyme to a particular substrate.
The induced-fit mode proposes that binding of substrate to the active site of an enzyme induces conformational changes in the enzyme which better positions various functional groups on the enzyme into the proper position to catalyse the reaction.
Answer:
11·699
Explanation:
Given the concentration of hydroxide ion in the solution is 5 × 
M
Assuming the temperature at which it is asked to find the pH of the solution be 298 K
<h3>At 298 K the dissociation constant of water is
</h3><h3>∴ pH + pOH = 14 at 298 K</h3><h3>pOH of the solution = -log( concentration of hydroxide ion )</h3>
∴ pOH of the given solution = - log(5 × = -0·699 + 3 = 2·301
pH of the given solution = 14 - 2·301 = 11·699
∴ pH of the solution = 11·699
Answer:
La agricultura intensiva puede eliminar rápidamente los nutrientes del suelo, que generalmente se repara con fertilizantes. La agricultura ecológica normalmente se refiere a no transgénicos
producción y falta de fertilizantes y pesticidas más dañinos. Por lo general, los productos orgánicos se venden a un precio más alto a las personas que creen que los conservantes afectan su salud y bienestar. Los productos intensivos generalmente se venden en grandes cadenas de mercado para obtener grandes ganancias y, por lo general, las frutas transgénicas se pueden producir en casi todas las estaciones.
intensive agriculture can remove nutrients from the soil quickly which is usually remedied by fertilizer. Organic farming normally refers to non-gmo
produce and lack of more harmful fertilizers and pesticides. Usually the organic produce is sold for a higher price to people who believe the preservatives affect their health and well being. Intensive produce is usually sold in large market chains for great profit and usually gmo fruits can be produced in almost all seasons.
Explanation:
espero que esto ayude.
0.050 litres of the water will be required to make a 3.91 M solution with 0.196 moles in it.
Explanation:
Data given:
moles of Cd
= 0.196 Moles
Molarity of the solution = 3.91 M
Volume in litres =?
molarity is calculated by the formula:
molarity = 
putting the values in the above formula and rearranging it for volume:
volume = 
volume = 
volume = 0.050 litres
0.050 litres of the water will be required to make a 3.91 M solution with 0.196 moles in it.
Molarity is the number of moles present in a given volume of solution which is given in litres. It is the measurement of the concentration of particular solute in a solution.
