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Vaselesa [24]
4 years ago
8

Consider the reaction 2 H 2 + O 2 ⟶ 2 H 2 O Δ H rxn = − 484 kJ Which answer best describes the transfer of heat that occurs when

1.60 mol H 2 reacts? 387 kJ absorbed 484 kJ released 387 kJ released 774 kJ absorbed 484 kJ absorbed 774 kJ released
Chemistry
1 answer:
9966 [12]4 years ago
6 0

Answer: 387 kJ energy is released

Explanation:

Endothermic reactions: These are the reactions in which energy is required in the reaction. The energy of the products are more than the energy of the reactants.\Delta H is positive.

Exothermic reactions: These are the reactions in which energy is released in the reaction. The energy of the products is less than the energy of the reactants.\Delta H is negative.

The given balanced equation is ;

2H_2+O_2\rightarrow 2H_2O  \Delta H=-484kJ

According to stoichioetry :

2 moles of hydrogen reacts to give = 484 kJ of heat

Thus 1.60 moles of hydrogen reacts to give =\frac{484}{2}\times 1.60=387kJ

Thus 387 kJ energy is released

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The correct equation for: iron + sulfur -> iron (III) sulfide is D
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Amphetamine (C9H13N)(C9H13N) is a weak base with a pKbpKb of 4.2. You may want to reference (Pages 710 - 713) Section 16.8 while
Soloha48 [4]

Answer:

pH = 10.38

Explanation:

  • C9H13N ↔ C9H20O3N+  +  OH-

∴ molar mass C9H13N = 135.21 g/mol

∴ pKb = - log Kb = 4.2

⇒ Kb = 6.309 E-5 = [OH-][C9H20O3N+] / [C9H13N]

∴ <em>C</em> sln = (205 mg/L )*(g/1000 mg)*(mol/135.21 g) = 1.516 E-3 M

mass balance:

⇒ <em>C</em> sln = 1.516 E-3 = [C9H20O3N+] + [C9H13N]......(1)

charge balance:

⇒ [C9H20O3N+] + [H3O+] = [OH-]; [H3O+] is neglected, come from water

⇒ [C9H20O3N+] = [OH-].......(2)

(2) in (1):

⇒ [C9H13N] = 1.516 E-3 - [OH-]

replacing in Kb:

⇒ Kb = 6.3096 E-5 = [OH-]² / (1.516 E-3 - [OH-])

⇒ [OH-]² + 6.3096 E-5[OH] - 7.26613 E-8 = 0

⇒ [OH-] = 2.3985 E-4 M

∴ pOH = - Log [OH-]

⇒ pOH = 3.62

⇒ pH = 14 - pOH = 14 - 3.62 = 10.38

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3 years ago
What is the term for a chemical reaction that uses more energy to break bonds than it releases when forming them?
Alchen [17]

Answer: Endothermic Reaction

Explanation:

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When an unsaturated hydrocarbon undergoes complete addition, the product is: a new unsaturated molecule a saturated molecule a s
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The product when an unsaturated hydrocarbon undergoes complete addition would be a saturated molecule. These saturated hydrocarbons becomes Alkanes where these molecules are only single-bonded in contrary to unsaturated hydrocarbons which have multiple bonds between atoms. 
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4 years ago
Read 2 more answers
For the net reaction: 2AB + 2C → A2 + 2BC, the following slow first steps have been proposed. AB → A + B 2C + AB → AC + BC 2AB →
puteri [66]

This is an incomplete question, here is a complete question.

For the net reaction: 2AB + 2C → A2 + 2BC, the following slow first steps have been proposed.

(1) AB → A + B

(2) 2C + AB → AC + BC

(3) 2AB → A₂ + 2B

(4) C + AB → BC + A

What rate law is predicted by each of these steps?

Answer : The rate law expression for the following reactions are:

(1) \text{Rate}=k[AB]

(2) \text{Rate}=k[C]^2[AB]

(3) \text{Rate}=k[AB]^2

(4) \text{Rate}=k[C][AB]

Explanation :

Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

The general reaction is:

A+B\rightarrow C+D

The general rate law expression for the reaction is:

\text{Rate}=k[A]^a[B]^b

where,

a = order with respect to A

b = order with respect to B

R = rate  law

k = rate constant

[A] and [B] = concentration of A and B reactant

Now we have to determine the rate law for the given reaction.

(1) The balanced equations will be:

AB\rightarrow A+B

In this reaction, AB is the reactant.

The rate law expression for the reaction is:

\text{Rate}=k[AB]

(2) The balanced equations will be:

2C+AB\rightarrow AC+BC

In this reaction, C and AB are the reactants.

The rate law expression for the reaction is:

\text{Rate}=k[C]^2[AB]

(3) The balanced equations will be:

2AB\rightarrow A_2+2B

In this reaction, AB is the reactant.

The rate law expression for the reaction is:

\text{Rate}=k[AB]^2

(4) The balanced equations will be:

C+AB\rightarrow BC+A

In this reaction, C and AB are the reactants.

The rate law expression for the reaction is:

\text{Rate}=k[C][AB]

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4 years ago
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