Mass of ammonia produced : 121.38 g
<h3>Further explanation</h3>
Given
Reaction
3H₂(g) + N₂(g) ⇒ 2NH₃(g)
100g of N₂
Required
Ammonia produced
Solution
mol of N₂ :
![\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{100}{28}\\\\mol=3.57](https://tex.z-dn.net/?f=%5Ctt%20mol%3D%5Cdfrac%7Bmass%7D%7BMW%7D%5C%5C%5C%5Cmol%3D%5Cdfrac%7B100%7D%7B28%7D%5C%5C%5C%5Cmol%3D3.57)
From the equation, mol ratio of N₂ and NH₃ = 1 : 2, so mol NH₃ :
![\tt \dfrac{2}{1}\times 3.57=7.14~moles](https://tex.z-dn.net/?f=%5Ctt%20%5Cdfrac%7B2%7D%7B1%7D%5Ctimes%203.57%3D7.14~moles)
mass of NH₃(MW=17 g/mol) :
![\tt mass=mol\times MW\\\\mass=7.14\times 17\\\\mass=121.38~g](https://tex.z-dn.net/?f=%5Ctt%20mass%3Dmol%5Ctimes%20MW%5C%5C%5C%5Cmass%3D7.14%5Ctimes%2017%5C%5C%5C%5Cmass%3D121.38~g)
Table salt is an ionic compound :)
Rate and Thanks!
Answer:
2.74 M
Explanation:
Given data:
Mass of sodium chloride = 80.0 g
Volume of water = 500.0 mL
Molarity of solution = ?
Solution:
Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.
Formula:
Molarity = number of moles of solute / L of solution
Now we will convert the mL into L.
500.0 mL× 1 L /1000 mL = 0.5 L
In next step we will calculate the number of moles of sodium chloride.
Number of moles = mass/molar mass
Number of moles = 80.0 g/ 58.4 g/mol
Number of moles = 1.37 mol
Molarity:
M = 1.37 mol/ 0.5 L
M = 2.74 M
The answer is (b) for example lemon juice is an acid and it tastes sour.
Hope this helps :).