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kenny6666 [7]
1 year ago
13

In the diagram, what is happening to the temperature at Point B?

Chemistry
1 answer:
taurus [48]1 year ago
8 0

In the diagram, an activity which is happening to the temperature at Point B is that: C. The temperature is not rising because the heat is being used to break the connections between the molecules.

<h3>What is matter?</h3>

Matter can be defined as any physical object or body that has both mass and takes up space. This ultimately implies that, the mass of a physical object measures the amount of matter the object contains.

<h3>What is heat?</h3>

In Science, heat is sometimes referred to as thermal energy and it can be defined as a form of energy that is transferred from a physical object (body) to another due to a difference in temperature.

By critically observing the diagram, we can reasonably infer and logically deduce that matter has dynamic states depending on the composition of its atoms and at point B the temperature remained constant (not rising) because the quantity of heat generated is used for breaking any form of connection between the molecules.

Read more on matter here: brainly.com/question/24783543

#SPJ1

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Determine the molecular formula of a compound that has a molar mass of 183.2 g/mol and an empirical formula of c2h5o2.
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C6H15O6

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What happens when the angle of the sun is perpendicular to the Earth's surface?
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Part B Change the distance of the electron from the center position as it moves up and down. What relationship do you notice bet
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The movement of the electron changes the amplitude of the wave. The farther the electron moves from the center position, the greater the amplitude.

Explanation:

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How many moles of CO2 are produced from the combustion of 5.25 moles of CH3OH?
iVinArrow [24]

First, we write the reaction for CH3OH combustion

CH3OH+3/2O2--->CO2+2H2O

for 1 mole of methanol, we get 1 mole of CO2, therefore for 5,25 moles of methanol we will get 5,25 moles of CO2

4 0
3 years ago
If 15.6 grams of copper (ii) chloride react with 20.2 grams of sodium nitrate how many grams of sodium chloride can be formed? W
olasank [31]

Answer:

- 13.56 g of sodium chloride are theoretically yielded.

- Limiting reactant is copper (II) chloride and excess reactant is sodium nitrate.

- 0.50 g of sodium nitrate remain when the reaction stops.

- 92.9 % is the percent yield.

Explanation:

Hello!

In this case, according to the question, it is possible to set up the following chemical reaction:

CuCl_2+2NaNO_3\rightarrow 2NaCl+Cu(NO_3)_2

Thus, we can first identify the limiting reactant by computing the yielded mass of sodium chloride, NaCl, by each reactant via stoichiometry:

m_{NaCl}^{by\ CuCl_2}=15.6gCuCl_2*\frac{1molCuCl_2}{134.45gCuCl_2} *\frac{2molNaCl}{1molCuCl_2} *\frac{58.44gNaCl}{1molNaCl} =13.56gNaCl\\\\m_{NaCl}^{by\ NaNO_3}=20.2gNaNO_3*\frac{1molNaNO_3}{84.99gNaNO_3} *\frac{2molNaCl}{2molNaNO_3} *\frac{58.44gNaCl}{1molNaCl} =13.89gNaCl

Thus, we infer that copper (II) chloride is the limiting reactant as it yields the fewest grams of sodium chloride product. Moreover the formed grams of this product are 13.56 g. Then, we take 13.56 g of sodium chloride to compute the consumed mass sodium nitrate as it is in excess:

m_{NaNO_3}^{by\ NaCl}=13.56gNaCl*\frac{1molNaCl}{58.44gNaCl}*\frac{2molNaNO_3}{2molNaCl} *\frac{84.99gNaNO_3}{1molNaNO_3}=19.72gNaNO_3

Therefore, the leftover of sodium nitrate is:

m_{NaNO_3}^{leftover}=20.2g-19.7g=0.5gNaNO_3

Finally, the percent yield is computed via:

Y=\frac{12.6g}{13.56g} *100\%\\\\Y=92.9\%

Best regards!

6 0
2 years ago
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