1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
otez555 [7]
3 years ago
15

What form of pollution can lichens be a good indicator of?

Chemistry
1 answer:
Natasha2012 [34]3 years ago
7 0

Answer:

Lichens can be used as air pollution indicators, especially of the concentration of sulphur dioxide in the atmosphere. Lichens are organisms that grow in exposed places such as rocks or tree bark. They need to be very efficient at absorbing water and nutrients to grow there.

You might be interested in
What has research determined about the orbit of an electron around a nucleus
polet [3.4K]
Hello,

Here is your answer:

The proper answer to this question is that "e<span>ach sub-level electron type has a unique path where it will likely to be found".

If you need anymore help feel free to ask me!

Hope this helps!</span>
4 0
3 years ago
Read 2 more answers
Which atmosphere layer is represented by F what are its characteristics
inysia [295]

That wouod be the ionosphere!

6 0
3 years ago
What is the mass number of oxygen atom with 7 neutrons?
kirill [66]
Oxygen has 8 protons
8 + 7 = 15
This isoptope is O-15
7 0
3 years ago
1. A 67 kg water-skier is being pulled by a speedboat. The force causes her to accelerate at 3.8
Alborosie

Answer:

254.6N

Explanation:

F=ma

F=67×3.8

F=254.6N

4 0
3 years ago
How many grams of Co2 are produced from 12 g of CH4 and 133 g of O2
Andru [333]

Answer:

m_{CO_2}=33gCO_2

Explanation:

Hello,

In this case the undergoing chemical reaction is:

CH_4+2O_2\rightarrow CO_2+2H_2O

Next we identify the limiting reactant with the given amounts of methane and oxygen by computing the available moles of methane and the moles of methane consumed by the 133 g of oxygen:

n_{CH_4}^{available}=12g*\frac{1mol}{16g} =0.75molCH_4\\n_{CH_4}^{consumed\ by\ O_2}=133gO_2*\frac{1molO_2}{32gO_2}*\frac{1molCH_4}{2molO_2}=2.08molCH_4

In such a way, the limiting reactant is methane with 0.75 moles which produce the following mass of carbon dioxide:

m_{CO_2}=0.75molCH_4*\frac{1molCO_2}{1molCH_4} *\frac{44gCO_2}{1molCO_2} \\\\m_{CO_2}=33gCO_2

Best regards.

7 0
3 years ago
Read 2 more answers
Other questions:
  • 1 times 2900 inches for a car
    6·1 answer
  • (2. Which of the following best describes humus?
    11·1 answer
  • Is it possible to add chemical formulas .
    12·2 answers
  • What is the relative rate of effusion for hydrogen iodide (128 g/mol) compared to gaseous hydrochloric acid (36.5 g/mol)
    14·1 answer
  • Find the pH of HCl with a concentration of 0.00006M<br> Round to the nearest whole number
    8·1 answer
  • People should be more concerned about the global water budget than the local water budget.
    9·1 answer
  • Scientists believe that interactions between atoms depend mostly on the arrangement of the outermost electrons in each atom. Thi
    15·1 answer
  • Giving Brainliest if u help me with this
    12·2 answers
  • Which of the following can be calculated from the mass of the reactants used in a chemical reaction?
    9·2 answers
  • How does the availibilty of water in various states affect weather ptterns
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!