Answer:
The angle of the incline above horizontal is 17.81 degrees.
Explanation:
Given that,
Mass of the object, m = 4 kg
Acceleration of the object above the incline, 
We need to find the angle of the incline above horizontal. The net force acting on the object along the incline is given by :






So, the angle of the incline above horizontal is 17.81 degrees. Hence, this is the required solution.
Answer:
The position nature and size of an image when an object placed at a distance equal to its focal length of rear view mirrors in vehicle will be
1) Position: Behind the mirror
2) Nature: Virtual
3) Size: Smaller than the object
Explanation:
Due to the nature and use of rear view mirrors, which are meant to enable the front facing driver visualize a wide area of the back portion of the vehicle, such that the images of the object will always remain smaller than the object, require a convex image
The image size, location, nature and orientation of an object placed in front of a convex mirror is diminished, behind the mirror of the upright, virtual, and upright
Therefore, the position nature and size of an image when an object placed at a distance equal to its focal length of rear view mirrors in vehicle will be
Position: Behind the mirror
Nature: Virtual
Size: Smaller than the object.
Explanation:
<u>Using Equations of Motion</u> :
(1) v = u + at
24 = 6.5 + a * 210
<u>a (Acceleration) = 0.083 m/s^2 </u>
<u>(</u><u>2</u><u>)</u><u> </u> v^2 = u^2 + 2aS
S = 576 - 42.25 / 0.166
<u>S (Distance travelled) = 3215.3 m </u>
(Option A seems a typo since the answer is 3215.3 m)
Answer:
The answer is below
Explanation:
The maximum height (h) of a projectile with an initial velocity of u, acceleration due to gravity g and at an angle θ with the horizontal is given as:

Given that the two projectile has the same height.


Answer:
e=58%
Explanation:
Given data
The Otto-cycle engine in a Mercedes-Benz SLK230 has a compression ratio of 8.8.
Solution
We want to calculate the ideal efficiency of the engine when ratio of heat capacity for gas used γ=1.40. Ideal efficiency (e) of the Otto cycle given by:

Substitute the given values to find efficiency e

e=58%