1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Elodia [21]
3 years ago
6

A listener triples his distance from a source that emits sound uniformly in all directions. by how many decibels does the sound

intensity level change?
Physics
1 answer:
Novay_Z [31]3 years ago
8 0
Sound intensity goes inversely as the square of the distance from the source. This is easy to understand if you think of the total sound energy spread out over the surface of a sphere with the source at the center. The surface area of the sphere goes as r^2, so the power density goes inversely as such.

The decibel change is simply

Change = 10 log10( (1/3)^2 ) = -9.54 dB
You might be interested in
5. A 4.00 kg object slides down a frictionless inclined plane with an acceleration of 3.00 m/s2. What is the angle of the inclin
Kazeer [188]

Answer:

The angle of the incline above horizontal is 17.81 degrees.

Explanation:

Given that,

Mass of the object, m = 4 kg

Acceleration of the object above the incline, a=3\ m/s^2

We need to find the angle of the incline above horizontal. The net force acting on the object along the incline is given by :

F_{net}=mg\ sin\theta

ma=mg\ sin\theta

a=g\ sin\theta

sin\theta=\dfrac{a}{g}

sin\theta=\dfrac{3}{9.8}

\theta=17.81^{\circ}

So, the angle of the incline above horizontal is 17.81 degrees. Hence, this is the required solution.

5 0
4 years ago
state position nature and size of an image when an object placed at an distance equal to its focal length of rear view in vehicl
maksim [4K]

Answer:

The position nature and size of an image when an object placed at a distance equal to its focal length of rear view mirrors in vehicle will be

1) Position: Behind the mirror

2) Nature: Virtual

3) Size: Smaller than the object

Explanation:

Due to the nature and use of rear view mirrors, which are meant to enable the front facing driver visualize a wide area of the back portion of the vehicle, such that the images of the object will always remain smaller than the object, require a convex image

The image size, location, nature and orientation of an object placed in front of a convex mirror is diminished, behind the mirror of the upright, virtual, and upright

Therefore, the position nature and size of an image when an object placed at a distance equal to its focal length of rear view mirrors in vehicle will be

Position: Behind the mirror

Nature: Virtual

Size: Smaller than the object.

5 0
3 years ago
A car enters a freeway with a speed of 6.5 m/s and accelerates to a speed of 24 m/s in 3.5 min. How far does the car travel whil
Vesna [10]

Explanation:

<u>Using Equations of Motion</u> :

(1) v = u + at

24 = 6.5 + a * 210

<u>a (Acceleration) = 0.083 m/s^2 </u>

<u>(</u><u>2</u><u>)</u><u> </u> v^2 = u^2 + 2aS

S = 576 - 42.25 / 0.166

<u>S (Distance travelled) = 3215.3 m </u>

(Option A seems a typo since the answer is 3215.3 m)

4 0
3 years ago
2. Two projectiles thrown from the same point at angles 0,=60° and 02=30° with the horizontal,
Liono4ka [1.6K]

Answer:

The answer is below

Explanation:

The maximum height (h) of a projectile with an initial velocity of u, acceleration due to gravity g and at an angle θ with the horizontal is given as:

h=\frac{u^2sin^2\theta}{2g}

Given that the two projectile has the same height.

For\ the\ first\ projectile\ with\ an\ angle\ \60^0 \ with\ the\ horizontal\ and initial\ velocity\ u_1:\\\\h=\frac{u_1^2sin^260}{2g} =\frac{0.75u_1^2}{2g} \\\\For\ the\ second\ projectile\ with\ an\ angle\ \30 \ with\ the\ horizontal\ and initial\ velocity\ u_2:\\\\h=\frac{u_2^2sin^230}{2g} =\frac{0.25u_2^2}{2g}\\\\\frac{0.25u_2^2}{2g}=\frac{0.75u_1^2}{2g}\\\\0.25u_2^2=0.75u_1^2\\\\\frac{u_1^2}{u_2^2} =\frac{0.25}{0.75} \\\\\frac{u_1^2}{u_2^2}=\frac{1}{3} \\\\\frac{u_1}{u_2}=\sqrt\frac{1}{3}

8 0
3 years ago
The Otto-cycle engine in a Mercedes-Benz SLK230 has a compression ratio of 8.8. What is the ideal efficiency of the engine? Use
vodomira [7]

Answer:

e=58%

Explanation:

Given data

The Otto-cycle engine in a Mercedes-Benz SLK230 has a compression ratio of 8.8.

Solution

We want to calculate the ideal efficiency of the engine when ratio of heat capacity for gas used  γ=1.40. Ideal efficiency (e) of the Otto cycle given by:

e=1-(\frac{1}{r^{Y-1} } )\\

Substitute the given values to find efficiency e

e=1-\frac{1}{8.8^{1.4-1} } \\e=0.58\\

e=58%

8 0
3 years ago
Other questions:
  • A skateboarder traveling at 7.0 meters per second rolls to a stop at the top of a ramp in 3.0 seconds. What is the skateboarder’
    10·1 answer
  • A trained attack octopus can crawl at a velocity of 0.3m/s. If the octopus crawls towards its victim for 30 seconds, what is the
    11·1 answer
  • What is the east component of a vector 15 m 15.0 o N of E?
    15·1 answer
  • Humberto builds two circuits using identical components.
    12·2 answers
  • A 1.2 kg ball drops vertically onto a floor, hitting with a speed of 20 m/s. it rebounds with an initial speed of 5.6 m/s. (a) w
    7·1 answer
  • Uranium was used to generate electricity in a nuclear reactor of a nuclear power station. The nuclear reactor was 29% efficient
    7·1 answer
  • A solid disk of radius 1.4 cm and mass 430 g is attached by a wire to one of its circular faces. It is twisted through an angle
    7·1 answer
  • Which ray diagram demonstrates the phenomenon of absorption?<br> tum
    9·1 answer
  • When the electrons reach the collector, they flow towards the positivly charged grid. The resulting current is measured. Note th
    11·1 answer
  • Please heeelllllppppppppp
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!