89 degrees Fahrenheit would be 31.7 degrees Celsius!
Answer:
823.46 kgm/s
Explanation:
At 9 m above the water before he jumps, Henri LaMothe has a potential energy change, mgh which equals his kinetic energy 1/2mv² just as he reaches the surface of the water.
So, mgh = 1/2mv²
From here, his velocity just as he reaches the surface of the water is
v = √2gh
h = 9 m and g = 9.8 m/s²
v = √(2 × 9 × 9.8) m/s
v = √176.4 m/s
v₁ = 13.28 m/s
So his velocity just as he reaches the surface of the water is 13.28 m/s.
Now he dives into 32 cm = 0.32 m of water and stops so his final velocity v₂ = 0.
So, if we take the upward direction as positive, his initial momentum at the surface of the water is p₁ = -mv₁. His final momentum is p₂ = mv₂.
His momentum change or impulse, J = p₂ - p₁ = mv₂ - (-mv₁) = mv₂ + mv₁. Since m = Henri LaMothe's mass = 62 kg,
J = (62 × 0 + 62 × 13.28) kgm/s = 0 + 823.46 kgm/s = 823.46 kgm/s
So the magnitude of the impulse J of the water on him is 823.46 kgm/s
When an unbalanced force acts on an object the change in the object state of rest or motion depends on the size and direction of the force.
If a body is at state of rest or motion, when an unbalanced external force acts on it, its starts moving in the direction of force and magnitude of its velocity or acceleration depends on the magnitude of force applied.
Hi there! :)
We can begin by doing a summation of forces on the ball. In the horizontal direction, we have the force of tension:
The tension force results in a centripetal force experienced by the ball. The equation of centripetal force is equivalent to:
= Centripetal force (N)
m = mass of ball (0.22 kg)
ω = angular speed of ball(? rad/sec, must convert rpm to rad/sec)
r = radius/length of string (1.0 m)
We must begin by converting rpm to rad/sec:
Now, we can set tension equal to the centripetal force and solve. 
Answer:
F = 183.153 N
Explanation:
given,
mass of the toothpick = 0.12 g = 0.00012 kg
initial velocity = 227 m/s
final velocity = 0 m/s
penetration depth = 16 mm = 0.016 m
using the equation of motion
v² - u² = 2 a s
0 - u² = 2 a s
- 221² = 2 × a × 0.016
a = 1526281.25 m/s²
Force is equal to
F = m a
= 0.00012 × 1526281.25
F = 183.153 N
