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Elenna [48]
3 years ago
7

A solid disk of radius 1.4 cm and mass 430 g is attached by a wire to one of its circular faces. It is twisted through an angle

of 10 o and released. If the spring has a torsion constant of 370 N-m/rad, what is the frequency of the motion
Physics
1 answer:
Neporo4naja [7]3 years ago
5 0

Answer:

    f= 4,186  10²  Hz

Explanation:

El sistema descrito es un pendulo de torsión que oscila con con velocidad angular, que esta dada por

             w = √ k/I

donde ka es constante de torsion de hilo e I es el momento de inercia del disco

El  momento de inercia de indican que giran un eje que pasa                 por enronqueces

           I= ½ M R2  

reduzcamos las cantidades al sistema SI

         R= 1,4 cm = 0,014  m

         M= 430 g = 0,430 kg

substituimos

           w= √ (2 k/M R2)

calculemos  

           w = RA ( 2 370 / (0,430  0,014 2)

           w = 2,963 103 rad/s

la velocidad angular esta relacionada con la frecuencia por

            w =2pi f

            f= w/2π

            f= 2,963 10³/ (2π)

            f= 4,186  10²  Hz

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3. A horizontally moving tennis ball barely clears the net, a distance y above the surface of the court. To land within the tenn
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(a) The ball’s maximum speed over the net is v(max) = √2gh.

(b) The maximum speed of the horizontally moving ball clearing the net is about 27 m/s.

(c) Speed of the ball is independent of its mass.

<h3>Time of motion of the ball</h3>

The time of motion of the ball is calculated as follows;

h = vt + ¹/₂gt²

1 = 0 + ¹/₂(9.8)t²

1 = 4.9t²

t² = 1/4.9

t² = 0.204

t = 0.452 s

<h3>Horizontal speed of the ball</h3>

The horizontal speed of the ball is calculated as follows;

X = vt

v = X/t

v = (12 m)/(0.452)

v = 26.6 m/s ≈ 27 m/s  (proved)

<h3>Conservation of energy</h3>

P.E = K.E

mgh = ¹/₂mv²

gh = ¹/₂v²

2gh = v²

√2gh = v(max)

Speed of the ball is independent of its mass.

Learn more about horizontal velocity here: brainly.com/question/24681896

#SPJ1

6 0
1 year ago
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