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Elenna [48]
3 years ago
7

A solid disk of radius 1.4 cm and mass 430 g is attached by a wire to one of its circular faces. It is twisted through an angle

of 10 o and released. If the spring has a torsion constant of 370 N-m/rad, what is the frequency of the motion
Physics
1 answer:
Neporo4naja [7]3 years ago
5 0

Answer:

    f= 4,186  10²  Hz

Explanation:

El sistema descrito es un pendulo de torsión que oscila con con velocidad angular, que esta dada por

             w = √ k/I

donde ka es constante de torsion de hilo e I es el momento de inercia del disco

El  momento de inercia de indican que giran un eje que pasa                 por enronqueces

           I= ½ M R2  

reduzcamos las cantidades al sistema SI

         R= 1,4 cm = 0,014  m

         M= 430 g = 0,430 kg

substituimos

           w= √ (2 k/M R2)

calculemos  

           w = RA ( 2 370 / (0,430  0,014 2)

           w = 2,963 103 rad/s

la velocidad angular esta relacionada con la frecuencia por

            w =2pi f

            f= w/2π

            f= 2,963 10³/ (2π)

            f= 4,186  10²  Hz

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6 0
1 year ago
While Bob is demonstrating the gravitational force on falling objects to his class, he drops an 1.0 lb bag of feathers from the
BartSMP [9]

In the experiment of free fall bob released a bag of mass 1 lb

so here we can say that initial speed of the bag is Zero

time taken by the bag to free fall is given as

t = 1.5 s

also the acceleration of free fall is given as

a = 9.8 m/s^2

now we will use kinematics equation here for finding the distance of free fall

d = v_i * t + \frac{1}{2} at^2

d = 0 + \frac{1}{2}*9.8* 1.5^2

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3 0
3 years ago
The y component of the electric field of an electromagnetic wave travelling in the +x direction through vacuum obeys the equatio
notsponge [240]

Answer:

λ =8.57 μ m

Explanation:

Given that

Ey = 375 cos [kx − (2.20 × 10¹⁴ rad/s)t] N/C

Standard form  

Ey=Eo cos[k x-ωt]  N/C

By comparing the given equation with the standard wave equation

Eo = 375 N/C

ω  = 2.20 × 10¹⁴ rad/s

We know that ω = 2 π f

f=\dfrac{\omega}{2\pi }

f=\dfrac{2.2\times 10^{14}}{2\pi }\ Hz

f=3.50×10¹³ Hz

We know that the velocity given as

V = f λ

λ =Wavelength

V=Speed = 3 x 10⁸ m/s

\lambda =\dfrac{V}{f }

\lambda =\dfrac{3\times 10^8}{3.5\times 10^{13}}\ m

λ =0.00000857 m              ( 1 μ m = 10⁶ m)

λ =8.57 μ m

8 0
3 years ago
Two 10-N weights are hanging from two Springs A and B. Spring A has a greater spring constant and therefore will ____. a. have a
arsen [322]
The spring should have a greater displacement .
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8 0
2 years ago
someone help me please haha Calculate the braking force of a lorry decelerating at a rate of 8 m/s² with a mass of 5000 kg.
ICE Princess25 [194]

Answer:

40000 N

Explanation:

Force: This cam be defined as the product of mass and acceleration.

From the question,

The braking force of the lorry will be the same in magnitude as the force at which the lorry is moving.

F = ma..................... Equation 1

Where m = mass of the lorry, a = acceleration/deceleration of the lorry.

Given: m = 5000 kg, a = 8 m/s²

Substitute these values into equation 1

F = 5000(8)

F = 40000 N

6 0
3 years ago
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