im guessing its about $10
Answer:
B. ![\left[\begin{array}{cc}\frac{9}{61} &\frac{2}{61} \\\frac{10}{61} &\frac{9}{61} \end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%5Cfrac%7B9%7D%7B61%7D%20%26%5Cfrac%7B2%7D%7B61%7D%20%5C%5C%5Cfrac%7B10%7D%7B61%7D%20%26%5Cfrac%7B9%7D%7B61%7D%20%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
The given matrix is
![\left[\begin{array}{cc}9&-2\\-10&9\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D9%26-2%5C%5C-10%269%5Cend%7Barray%7D%5Cright%5D)
The determinant of this matrix is
![=9\times9--10\times-2=61](https://tex.z-dn.net/?f=%3D9%5Ctimes9--10%5Ctimes-2%3D61)
Since the determinant is not zero, it means the inverse exists.
The inverse is given by
![\frac{1}{determinant}\left[\begin{array}{cc}9&--2\\--10&9\end{array}\right]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bdeterminant%7D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D9%26--2%5C%5C--10%269%5Cend%7Barray%7D%5Cright%5D)
![\frac{1}{61}\left[\begin{array}{cc}9&2\\10&9\end{array}\right]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B61%7D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D9%262%5C%5C10%269%5Cend%7Barray%7D%5Cright%5D)
![\left[\begin{array}{cc}\frac{9}{61} &\frac{2}{61} \\\frac{10}{61} &\frac{9}{61} \end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%5Cfrac%7B9%7D%7B61%7D%20%26%5Cfrac%7B2%7D%7B61%7D%20%5C%5C%5Cfrac%7B10%7D%7B61%7D%20%26%5Cfrac%7B9%7D%7B61%7D%20%5Cend%7Barray%7D%5Cright%5D)
The correct choice is B.
Answer:
- 2 and 7
Step-by-step explanation:
A polynomial P(x) divided by (x + h) has remainder f(- h) ← remainder theorem
P(x) divided by (x + 5) has remainder P(- 5) = - 2 ( from result given )
P(x) divided by (x - 3) has remainder P(3) = 7 ( from result given )
function is: f(x)=(x+10)^2