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Georgia [21]
3 years ago
15

What sort of evidence would support at least one of the components of the

Chemistry
1 answer:
Yuki888 [10]3 years ago
8 0

Answer:

(not sure) The origin of all cells observed can be traced to previous cells

Explanation:

- not all cells convert energy (?) (this I'm not sure but think so? might be wrong tho)

- not all cells have cell walls e.g. animal cells only have the cell membrane, no cell wall

- Rocks and other nonliving things are composed of cells: non living things are composed of the elements and not cells (unless they were previously alive, then they contain dead cells)

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A fish is removed from a contaminated lake. You determine that a particular toxin (X) is present in its cells at concentration X
netineya [11]
The level of toxins in the fish's cell is equivalent to the level of toxins in the water. Therefore, in order to reduce the toxins further, we should replace the now contaminated water with clean water. After the level of toxins in the fish's cell stops reducing, we replace the water with clean water once again.
3 0
3 years ago
When the products of a reaction have less energy than the reactants
ohaa [14]

Answer:

the energy of the products is less than the energy of the reactants.

Explanation:

the the change is enthalpy is negative, and heat is released to the surroundings.

7 0
3 years ago
The NaCl crystal structure consists of alternating Na⁺ and Cl⁻ ions lying next to each other in three dimensions. If the Na⁺ rad
Yuliya22 [10]

Answer : The radii of the two ions Cl⁻ ion and Na⁺ ion is, 181 and 102 pm respectively.

Explanation :

As we are given that the Na⁺ radius is 56.4% of the Cl⁻ radius.

Let us assume that the radius of Cl⁻ be, (x) pm

So, the radius of Na⁺ = x\times \frac{56.4}{100}=(0.564x)pm

In the crystal structure of NaCl, 2 Cl⁻ ions present at the corner and 1 Na⁺ ion present at the edge of lattice.

Thus, the edge length is equal to the sum of 2 radius of Cl⁻ ion and 2 radius of Na⁺ ion.

Given:

Distance between Na⁺ nuclei = 566 pm

Thus, the relation will be:

2\times \text{Radius of }Cl^-+2\times \text{Radius of }Na^+=\text{Distance between }Na^+\text{ nuclei}

2\times x+2\times 0.564x=566

2x+1.128x=566

3.128x=566

x=180.9\approx 181pm

The radius of Cl⁻ ion = (x) pm = 181 pm

The radius of Na⁺ ion = (0.564x) pm = (0.564 × 181) pm =102.084 pm ≈ 102 pm

Thus, the radii of the two ions Cl⁻ ion and Na⁺ ion is, 181 and 102 pm respectively.

4 0
3 years ago
What is thr valency of scadium
Hoochie [10]

scandium is a transition metal and shows a valency of 3.

4 0
3 years ago
Boron<br> B<br> 10.811<br> Number of neutrons
andrew-mc [135]

Answer:

6

Explanation:

To determine the number of neutrons we round 10.8 to 11 and subtract the atomic number (5) and get 6; therefore, boron has 6 neutrons.

7 0
3 years ago
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