A sample of SO2 gas occupies 45.6 L at 373 K and 3.45 atm. This sample contains how many moles of oxygen atoms?

Chemistry

1 answer:

lisov135 [29]3 years ago

5 0

Answer:

10.28 mol

Explanation:

S + 2O = SO2

(atm x L) ÷ (0.0821 x K)

(3.45 x 45.6) ÷ (0.0821 x 373)

=5.13726

Then round it to significant figures

=5.14

5.14 mol SO2 x (2 mol O ÷ 1 mol SO2)

=10.28 mol O

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balu736 [363]

Answer:

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