Yo sup??
The correct answer is option C
the rest are aldehyde, carboxylic acid and ether respectively.
Hope this helps.
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Answer:
1.3 × 10⁴ mL
Explanation:
A Pb-contaminated water sample contains 0.0012 %Pb by mass, that is, there are 0.0012 g of Pb in 100 g of solution. The mass of the sample that contains 150 mg (0.150 g) of Pb is:
0.150 g Pb × (100 g sample/0.0012 g Pb) = 1.25 × 10⁴ g sample
The density of the sample is 1.0 g/mL. The volume of the sample is:
1.25 × 10⁴ g × (1 mL/1.0 g) = 1.3 × 10⁴ mL
