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Helen [10]
3 years ago
11

What is the mass of 2.542 × 1026 atoms of F?

Chemistry
1 answer:
stiks02 [169]3 years ago
8 0

Answer:

7.98 × 10^3grams.

Explanation:

To find the mass of fluorine in the number of atoms provided, we first divide the number of atoms by Avagadros number (6.02 × 10^23atoms) to get the number of moles in the fluorine atom. That is;

number of moles (n) = number of atoms (nA) ÷ 6.02 × 10^23 atoms

n = 2.542 × 10^26 ÷ 6.02 × 10^23

n = 0.42 × 10^ (26-23)

n = 0.42 × 10^3

n = 4.2 × 10^2moles

Using mole = mass ÷ molar mass

Molar/atomic mass of fluorine (F) = 19g/mol

mass = molar mass × mole

Mass (g) = 19 × 4.2 × 10^2

Mass = 79.8 × 10^2

Mass = 7.98 × 10^3grams.

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stira [4]

Answer:

FLUORINE

Explanation:

It has 5 electrons In Its 2P shell!

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The correct answer is D. magnetic bond
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In IR spectroscopy, we normally talk about "frequencies" when in reality we are referring to wavenumbers. What is the mathematic
Svetach [21]

Answer:

Here's what I get.

Explanation:

(b) Wavenumber and wavelength

The wavenumber is the distance over which a cycle repeats, that is, it is the number of waves in a unit distance.

\bar \nu = \dfrac{1}{\lambda}

Thus, if λ = 3 µm,

\bar \nu = \dfrac{1}{3 \times 10^{-6} \text{ m}}= 3.3 \times 10^{5}\text{ m}^{-1} = \textbf{3300 cm}^{-1}

(a) Wavenumber and frequency

Since

λ = c/f and 1/λ = f/c

the relation between wavenumber and frequency is

\bar \nu = \mathbf{\dfrac{f}{c}}

Thus, if f = 90 THz

\bar \nu = \dfrac{90 \times 10^{12} \text{ s}^{-1}}{3 \times 10^{8} \text{ m$\cdot$ s}^{-1}}= 3 \times 10^{5} \text{ m}^{-1} = \textbf{3000 cm}^{-1}

(c) Units

(i) Frequency

The units are s⁻¹ or Hz.

(ii) Wavelength

The SI base unit is metres, but infrared wavelengths are usually measured in micrometres (roughly 2.5 µm to 20 µm).

(iii) Wavenumber

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8 0
3 years ago
A 32.5 g iron rod, initially at 22.4 ∘C, is submerged into an unknown mass of water at 63.0 ∘C, in an insulated container. The f
Allisa [31]

Answer:

The mass of water m_{w} = 39.18 gm

Explanation:

Mass of iron m_{iron} = 32.5 gm

Initial temperature of iron T_{1} = 22.4°c = 295.4 K

Specific heat of iron  C_{iron} = 0.448 \frac{KJ}{kg K}

Mass of water = m_{w}

Specific heat of water  C_{w} = 4.2 \frac{KJ}{kg  K}

Initial temperature of water T_{2} = 336 K  

Final temperature after equilibrium T_{f} = 59.7°c = 332.7 K

When iron rod is submerged into water then

Heat lost by water  = Heat gain by iron rod

m_{w} C_{w} (T_{2} - T_{f} ) =  m_{iron} C_{iron} ( T_{f} - T_{1} )

Put all the values in above formula we get

m_{w} × 4.2 × ( 336 - 332.7 ) = 32.5 × 0.448 × ( 332.7 - 295.4 )

m_{w} = 39.18 gm

Therefore the mass of water m_{w} = 39.18 gm

8 0
2 years ago
I need help please with this chemistry work ​
Marysya12 [62]

Answer:

question 1: 3

question 2: the number of Valence electrons in the atom

hope it helps

8 0
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