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Nimfa-mama [501]
3 years ago
14

A poll was conducted to determine what percentage of the peoplesupport a certain candidate for the U.S. Senate.400 people were s

urveyed, and44% of them said they support thecandidate. If we require a confidence level of99%, what margin of error do we report?
Mathematics
1 answer:
seropon [69]3 years ago
6 0

Answer: 0.064

Step-by-step explanation:

The formula to find the margin of error :-

E=z_{\alpha/2}\sqrt{\dfrac{p(1-p)}{n}}

Given : Significance level : \alpha=1-0.99=0.01

Critical value : z_{\alpha/2}=2.576

Sample size : n=400

The proportion of people support the candidate :p=0.44

Then , E=(2.576)\sqrt{\dfrac{0.44(1-0.44)}{400}}\approx0.064

Hence, Margin of error = 0.064

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Please again sorry help me last one
Bezzdna [24]

Answer:

$3.41

Step-by-step explanation:

262.94 + 83.65 = 346.59

350.00 - 346.59 = 3.41

5 0
4 years ago
Your goal is to create a college fund for your child. Suppose you find a fund that offers an APR of 4 %. How much should you dep
Alisiya [41]

Answer:

$701.12

Step-by-step explanation:

Before doing the computing, notice that if we increase an amount D in,say,  r%, it means that the new amount obtained is D+r% of D = D+(r/100)D = D(1+r/100).

That is to say, increasing an amount D in r% is equivalent to multiplying it by (1+r/100)

Taking into account that <em>APR stands for Annual Percentage Rate</em>, the amount we deposit will be increased 4% each year.  

Generally, in this kind of loans <em>the percentage is prorated monthly</em>. That is to say, <em>the money you have in the account will be increased in (4/12)%= 0.3333% each month. </em>

Let D be the amount we are going to deposit each month.

After the month 1 we will have the money increased in 0.3333% plus the new deposit

D(1+\frac{0.3333}{100})+D=D(1+1.0033)

After the month 2 we will have the money we already had increased in 0.3333% plus the new deposit D

D(1+1.0033)(1.0033)+D=D(1.0033+1.0033^2)+D=D(1+1.0033+1.0033^2)

After the month 3 we will have, for the same reason,

D(1+1.0033+1.0033^2+1.0033^3)

It can be noticed then, that after 18 years (96 moths) we will have an amount in the fund of

D(1+1.0033+1.0033^2+...+1.0033^{96})

If we call  

S=1+1.0033+1.0033^2+...+1.0033^{96}

then

1.0033S=1.0033+1.0033^2+...+1.0033^{96}+1.0033^{97}

Subtracting the equations

S-1.0033S=1-1.0033^{97}\Rightarrow S(1-1.0033)=1-1.0033^{97}

and we have

S=\frac{1-1.0033^{97}}{1-1.0033}=114.10298

So, after 18 years the amount in the fund will be

114.10298D

If we want this amount to be $80,000 then 114.10298D=80,000

D=\frac{80,000}{114.10298}\approx \$ 701.12

So, the money we would have to deposit each month in a fund with an APR of 4% to accumulate $80,000 in 18 years, is

\boxed{D=\$701.12}

5 0
3 years ago
Show work, please!
jolli1 [7]
Let's try this.
First, we have the absolute value of -4(-2)-8, or the absolute value of 8-8, so 0.
Let's forget about that, now. It's 0, it adds no value. Let's not worry about it.
For the next, we see the absolute value of -1-(-2)^2
Or:
-1-4, or -5.
Next is 2(-2)^2, or 2(4) = 8.
Therefore, we have -5+8 =3.
If you see any errors, let me know.
Otherwise, I hope this helps!
6 0
3 years ago
NEED HELP WITH PERFORMANCE TASK IN MATH!!! I will mark you brainliest and give you extra points!
koban [17]

Answer:

a) Use the data in the table to find the rate of change in the length of baby girl Grace. (2 points)

The rate of change is 1.5 inches every two months. (0.7 inches per month)


b) Write a linear equation for the graph in point-slope form. Show your work. (2 points)

0.7x-y+17.2=0

Work: (y-y1)=m(x-x1)

(y-20)=0.7(x-4)

y=0.7x-2.8+20

y=0.7x+17.2

0.7x-y+17.2=0


c) 20-1.5= 18.5 (2 months)

18.5-1.5= 17

17 inches

Grace was 17 inches at birth. I found this out by using my data and knowing that she grew 1.5 inches every two months. So, to solve I subtracted 1.5 from 20, for that was the first data that was given, and was left with the data that the baby was 18.5 inches long at birth. I did the same procedure again, subtracting 1.5 from 18.5, and was given 17. Since 17 inches long was what was recorded at zero months, that would mean that the baby was 17 inches long at birth.


d) Based on the data, I can predict that Grace will grow about 4.2- 4.5 inches in 6 months, and be about 44 inches long. To do this, I took the known rate of change (1.5 inches per two months) and the last recorded data (39.5 inches). I then realized that there was six months until 36 weeks. Still keeping in mind that the rate of change was 1.5 per two months, I multiplied 1.5 by 6 and then divided by 2 (because it was every two months and not one). This came out to be that she would grow 4.5 inches in 6 months. I then added 4.5 to 39.5 (the length at 30 months) and got a total of 44 inches. This would mean that Grace would be 44 inches long at 36 weeks. This would make sense because the rate of change was used, and if one subtracted the rate of change by 0.7 for 6 months from 44, they would get an answer of 39.5.


Hope this helped:)


3 0
3 years ago
If the original volume of a cone is 32cm^3 and the height is tripled, what is the resulting volume of the new cone?
yarga [219]

Answer:

D

Step-by-step explanation:

3 0
3 years ago
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