Question

A bowling ball of mass 8 kg hits a wall going 5 m/s and rebounds at a speed of 4 m/s. What was the impulse applied to the bowling ball?
A. 40 kg'm/s
B. 32 kg'm/s
C. 72 kg'm/s
D. 8 kg'm/s

Answer 1

Yo, sorry I just resized I am so dumb.

The Answer would be C.

Becuase the wall is pushing off 9 becuase it took 5 and bounced back off 4 so 

9 times 8= 72 kg m/s 

Sorry about that ):

Answer 2

Answer:

Impulse, J = 72 kg-m/s

Explanation:

It is given that,

Mass of the ball, m = 8 kg

Initial velocity of the ball, u = 5 m/s

Final velocity of the ball, v = -4 m/s (as it rebounds back)

We need to find the impulse applied to the bowling ball. We know that impulse is equal to the change in momentum of an object i.e.

$J=m(v-u)$

$J=8\ kg\times (-4\ m/s-5\ m/s)$

J = -72 kg-m/s

Negative sign shows the impulse is applied in opposite direction. So, the correct t option is (c). Hence, this is the required solution.