velocity of object just before hitting the ground = 10 m/s
10 m/sExplanation:
here's the solution : -
=》mechanical energy is always constant, when the object is at the top of the building , the object has potential energy but no kinetic energy,
so, at the top of the building the mechanical energy = potential energy = 100 J
but at when it is dropped from the building, the whole potential energy get converted into kinetic energy, just before reaching the bottom .
so, mechanical energy in the object just before hitting the ground = kinetic energy
( potential energy = 0 )
So, kinetic energy = 100 J
now, we know
=》
( since, mass = 2 kg )
=》
=》
=》
so, velocity of object just before hitting the ground = 10 m/s
Answer:
4N
Explanation:
Given parameters:
Weight of stone when immersed in water = 18N
Weight of water displaced = 4N
Unknown:
Weight of the stone in air = ?
Solution:
To solve this problem, we employ the Archimedes' principles.
It states that the upward buoyant force on a body is equal to the weight of the fluid displaced.
The weight of the water displaced is equal to the weight of the body.
So, the weight of the stone in air = 4N
Object that the red is being bounced off of if the objects only absorbs a bit of purple/violet you have a red-violet <span />
Answer:
Q1: (a)
so
Q2:
this is the radius in meter
diameter = 2r
in this i don't know which choice is the right answer
Q3:
so
again there is no correct answer
Answer:
Explanation:
Time to mow 1 lawn by Wilma is 80 minutes
so work done in 1 minute by Wilma is given as
Similarly Rocky mow same lawn in 120 minute
so work done in 1 minute by Rocky is given as
now we know that they both worked by "t" time
so total work performed by them
they both mow 2 lawns then it is given as