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3 years ago

The longer the lever, the greater the

Physics

1 answer:

Simora [160]3 years ago

4 0

Answer: The longer the lever, the greater the force on the load will be.

Explanation:

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Which products are formed when ethane (C2H6) undergoes combustion?

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It is C.

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Physical Science AIS - AE 20-21-Kotal / Unit 2: Reactions and Radioactivity / The Environment

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The epidermis contains melanocytes, pigment cells that produce

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melanin

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Jason launches a model rocket with a mass of 2.0 kg from his spring-powered rocket launcher with a spring constant of 800 N/m. H

Arada [10]

Answer:

121 Joules

6.16717 m

Explanation:

m = Mass of the rocket = 2 kg

k = Spring constant = 800 N/m

x = Compression of spring = 0.55 m

Here, the kinetic energy of the spring and rocket will balance each other

$\frac{1}{2}mu^2=\frac{1}{2}kx^2\\\Rightarrow u=\sqrt{\frac{kx^2}{m}}\\\Rightarrow u=\sqrt{\frac{800\times 0.55^2}{2}}\\\Rightarrow u=11\ m/s$

The initial velocity of the rocket is 11 m/s = u.

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.81 m/s² = g

$v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-11^2}{2\times -9.81}\\\Rightarrow s=6.16717\ m$

The maximum height of the rocket will be 6.16717 m

Potential energy is given by

$P=mgh\\\Rightarrow P=2\times 9.81\times \frac{0^2-11^2}{2\times -9.81}\\\Rightarrow P=121\ J$

The potential energy of the rocket at the maximum height will be 121 Joules

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4 years ago

A flowerpot falls off a windowsill and falls past the window below. You may ignore air resistance. It takes the pot 0.380 ss to

kirill [66]

Answer:

The top of the window is 0.5 m below the sill of the upper window

Explanation:

We have the time the pot takes to fall a distance y- yo = 2.0 m and g = 9.8, from this we can calculate the velocity of the pot when it just reached the top of the window in question. Take the positive y direction to be downward

y-yo=vo*t+I/2gt^2

vo=(y-yo-I/2gt^2)/t

vo=3.138 m/s

The flowerpot falls from rest and we have the velocity it gains until it reaches the top of the window below, from this information we can get the distance between the sill and the top of the window below.

v^2=vo^2+2g(y-yo)

y-yo=(v^2-vo^2)/2g

= 0.5 m

The top of the window is 0.5 m below the sill of the upper window

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4 years ago