Answer: The amount of water formed is 12 moles
Explanation: Please see the attachments below
Answer: 162.8 grams
Explanation:
Magnesium nitrate has a chemical formula of Mg(NO3)2.
Given that:
Number of moles of Mg(NO3)2 = 1.1 moles
Mass in grams of Mg(NO3)2 = ?
For Molar mass of Mg(NO3)2, use atomic mass of magnesium = 24g, nitrogen = 14g, oxygen = 16g
Mg(NO3)2 = 24g + (14g + 16gx3) x 2
= 24g + (14g + 48g) x 2
= 24g + (62g) x 2
= 24g + 124g
= 148g/mol
Now, apply the formula:
Number of moles = Mass in grams / molar mass
1.1 moles = Mass / 148g/mol
Mass = 1.1 moles x 148g/mol
Mass = 162.8 grams
Thus, there are 162.8 grams of magnesium nitrate.
Answer:

Explanation:
The reaction is
KOH(aq) + HNO₃(aq) ⟶ KNO₃(aq) + H₂O(ℓ)
If you evaporate the water, the solid substance is the compound, potassium nitrate.

KNO₃(aq) ⟶ KNO₃(s)
solution:
density x volume=mass volume x volume
13.6gml x 3.55ml
thus,the object has a mass of 98.3g