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umka2103 [35]
3 years ago
8

Complete the analogy solid:Table:.......water​

Chemistry
1 answer:
prisoha [69]3 years ago
4 0

Answer:

of

Explanation:

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Which of the following is a biotic part of an environment?<br> mud<br> clams<br> sunshine<br> rocks
fredd [130]

Answer:

sunshine

Explanation:

because it's light u get it from the ecosystem

7 0
3 years ago
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For each of the following, use the periodic table to determine the number of valence electrons in an atom of the element.
Kipish [7]

Explanation:

Ne 8. S 6. Mg 2. Sn 4. C 4. Al 3. Te 6. Cs 1. Bi 5. Br 7. Ga 3. P 5.

5 0
3 years ago
2NaClO3 ——&gt; 2NaCl + 3O2
Alborosie

Answer:  

<h3>1) 208.09 g</h3><h3>2) 7.11 × 10²² particles</h3>

<h2>Explanation:</h2><h3>NUMBER ONE</h3>

<u>Find moles of Known Substance (NaCl)</u>

Moles of NaCl = mass ÷ molar mass

                        =  114.25 g ÷ 58.44 g/mol

                        = 1.955 mol

<u>Use Mole Ratio of Known to Unknown (NaCl : NaClO₃) to Determine Moles of Unknown</u>

The mole ratio of NaCl to NaClO₃ is 2 to 2 or simply 1 to 1.

This means that for each mole of NaCl produced the same number of moles of NaClO₃ was decomposed.

∴ since moles of NaCl = 1.955 mol,

then moles of NaClO₃ = 1.955 mol

<u>Find Mass of Unknown </u>

Mass of NaClO₃ = moles × molar mass

                           = 1.955 mol × 106.44 g/mol

                           =  208.09 g

<h3>NUMBER TWO</h3>

<u>Determine the Moles of Known (O₂)</u>

moles of O₂ = (volume × density) ÷ molar mass

                    = (68.30 L × 0.0828 g/L) ÷ 32 g/mol

                    = 0.177 mol

<u>Use Mole Ratio of Known to Unknown (O₂ : NaClO₃) to Determine Moles of Unknown</u>

Mole ratio of O₂ : NaClO₃ is 3 : 2. Therefore for each mole of oxygen produced, ²/₃ the moles of NaClO₃ is produced.

∴ if moles of O₂  =  0.177 mol

then moles of NaClO₃ =  0.177 mol × ²/₃

                                     = 0.118 mol

<u>Find the Number of Particles of Unknown</u>

Number of particles  = moles × Avogadro's Number

                                  = 0.118 mol × (6.022 × 10²³ particles/mol)

                                  =  7.11 × 10²² particles

3 0
3 years ago
In this nuclear reaction equation, oxygen decays to form nitrogen. Which equation correctly describes
sertanlavr [38]

Answer: Its A

Explanation:

6 0
3 years ago
What is the mass of an original 5.60-gram sample of iron-53 that remains unchanged after 25.53 minutes?
olga_2 [115]
Answer is 0.7 g

Reason: Given: mass of Fe = 5.60 gWe know that, half life of Fe-53 = t1/2 (Fe-53) = 8.51 min.
Thus, after 25.53 mins, number of half life passed = 25.53/8.51= 3

Now, Amount left after first half life = 5.60g/2 = 2.80 g
Amount left after second half life = 2.80g/2 = 1.40 g
Amount left after third half-life = 1.40g/2 = 0.7g.
4 0
4 years ago
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