What is the pH of 0.0001 M NaOH

1 answer:

5 0

Well. NaOH is a base. That's the first thing you need to watch for.
So to find the pOH, you take -log(.0001)
that would be 4. So now you have the pOH and you still need to find the pH
To find pH from pOH, you take 14(the maximum pH,sorta)-pOH(in this case 4)
14-4=10 The pH of NaOH is 10

You might be interested in

What characterizes a homogeneous mixture?

Vadim26 [7]

It has the same composition throughout, unlike a heterogeneous which has visibly separate substances

4 0

3 years ago

Assuming 100% dissociation, calculate the freezing point and boiling point of 3.11 m K3PO4(aq). Constants may be found here.

aivan3 [116]

Do u have a picture

5 0

2 years ago

Briefly compare and contrast the relative resistance to ph change of the seven solutions

JulsSmile [24]

PH stands for "Potential Hydrogen" and the PH scale ranges from 0-14. PH refers to the ability to attract hydrogen ions.

The PH of a solution either indicates acidity of the solution or alkalinity of the solution. A solution which has PH 7 above is a base solution where a solution with PH less than 7 is an acidic solution.

6 0

3 years ago

Atomic numbers of atoms of elements _____ as you read _____ along each row of the periodic table of the elements.

serious [3.7K]

The periodic table increases as you read left to right so it is A.

8 0

3 years ago

Read 2 more answers

For the reaction Na2CO3+Ca(NO3)2⟶CaCO3+2NaNO3 how many grams of calcium carbonate, CaCO3, are produced from 79.3 g of sodium car

Alexus [3.1K]

Answer:

74.81 grams of calcium carbonate are produced from 79.3 g of sodium carbonate.

Explanation:

The balanced reaction is:

Na₂CO₃ + Ca(NO₃)₂ ⟶ CaCO₃ + 2 NaNO₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:

Na₂CO₃: 1 mole
Ca(NO₃)₂: 1 mole
CaCO₃: 1 mole
NaNO₃: 2 mole

Being the molar mass of the compounds:

Na₂CO₃: 106 g/mole
Ca(NO₃)₂: 164 g/mole
CaCO₃: 100 g/mole
NaNO₃: 85 g/mole

then by stoichiometry the following quantities of mass participate in the reaction:

Na₂CO₃: 1 mole* 106 g/mole= 106 g
Ca(NO₃)₂: 1 mole* 164 g/mole= 164 g
CaCO₃: 1 mole* 100 g/mole= 100 g
NaNO₃: 2 mole* 85 g/mole= 170 g

You can apply the following rule of three: if by stoichiometry 106 grams of Na₂CO₃ produce 100 grams of CaCO₃, 79.3 grams of Na₂CO₃ produce how much mass of CaCO₃?

$mass of CaCO_{3} =\frac{79.3 grams of Na_{2} CO_{3} *100 grams of of CaCO_{3}}{106 grams of Na_{2} CO_{3}}$

mass of CaCO₃= 74.81 grams

74.81 grams of calcium carbonate are produced from 79.3 g of sodium carbonate.

6 0

3 years ago