The precipitation reactions :
2KBr + Pb(NO₃)₂ -----> PbBr₂ + 2KNO₃
Hg₂(C₂H₃O₂)₂ + 2NaI ----> Hg₂I₂ + 2NaC₂H₃O₂
Ba(NO₃)₂ + K₂SO₄ -----> BaSO₄ + 2KNO₃
<h3>Further explanation </h3>There are two types of chemical reactions that may occur,
namely single-replacement reactions and double-replacement reactions.
1. A single replacement reaction is a chemical reaction in which one element replaces the other elements of a compound to produce new elements and compounds
Not all of these reactions can occur. We can use the activity series, which is a list of elements that can replace other elements below / to the right of them in a single replacement reaction.
2. Double-Replacement reactions. Happens if there is an ion exchange between two ion compounds in the reactant to form two new ion compounds in the product
To predict whether this reaction can occur or not is to see the precipitation reaction. A precipitation reaction occurs if two ionic compounds which are dissolved reacted to produce one of the products of the ion compound does not dissolve. Formation of these precipitating compounds that cause reactions can occur
Solubility Rules:
All compounds of Li +, Na +, K +, Rb +, Cs +, and NH4 +
All compounds of NO₃⁻ and C₂H₃O₂⁻
Compounds of Cl−, Br−, I− except Ag⁺, Hg₂²⁺, Pb²⁺
Compounds of SO₄²⁻ except Hg₂²⁺, Pb²⁺, Sr²⁺, Ba²⁺
Compounds of CO₃²⁻ and PO₄³⁻ except for Compounds of Li +, Na +, K +, Rb +, Cs +, and NH₄ +
Compounds of OH− except Compounds of Li +, Na +, K +, Rb +, Cs +, NH₄⁺, Sr²⁺, and Ba²⁺
Let's look at possible reactions that are not shown in the question
1. S + O₂ ---> SO₂
SO₂ = gas so this reaction not the precipitation reactions
2. H₂O₂ + NaIO ---> NaI + H₂O + O₂
NaI = soluble so this reaction not the precipitation reactions
3. 2KBr + Pb(NO₃)₂ -----> PbBr₂ + 2KNO₃
PbBr₂ precipitates = so this reaction the precipitation reactions
4. HCl + KOH ----> KCl + H₂O
KCl soluble so this reaction not the precipitation reactions
5. HBr + KOH ----> KBr + H₂O
KBr soluble so this reaction not the precipitation reactions
6. Hg₂(C₂H₃O₂)₂ + 2NaI ----> Hg₂I₂ + 2NaC₂H₃O₂
Hg₂I₂ precipitates = so this reaction the precipitation reactions
7. Ba(NO₃)₂ + K₂SO₄ -----> BaSO₄ + 2KNO₃
BaSO₄ precipitates = so this reaction the precipitation reactions
<h3>Learn more</h3>
the rate of a chemical reaction
the reducing agent
substance loses electrons in a chemical reaction
Keywords: a double-replacement equation, A single-replacement reaction
Answer:
%age Yield = 85.36 %
Solution:
The Balance Chemical Reaction is as follow,
C₆H₁₂O + Acid Catalyst → C₆H₁₀ + Acid Catalyst + H₂O
According to Equation ,
100 g (1 mole) C₆H₁₂O produces = 82 g (1 moles) of C₆H₁₀
So,
4.0 g of C₆H₁₂O will produce = X g of C₆H₁₀
Solving for X,
X = (4.0 g × 82 g) ÷ 100 g
X = 3.28 g of C₆H₁₀ (Theoretical Yield)
As we know,
%age Yield = (Actual Yield ÷ Theoretical Yield) × 100
%age Yield = (2.8 g ÷ 3.28 g) × 100
%age Yield = 85.36 %
