Which of the following provides the best analogy for an electron in an atomic orbital
1 answer:
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Answer:
D) 6.02 kJ/mol
Explanation:
Hello,
In this case, since 200kJ melted 1.5 kg of ice (2.0kg-0.5kg), we can compute the melted moles:
Then, we compute the molar enthalpy of fusion by diving the melted moles to the applied heat:
Hence answer is D) 6.02 kJ/mol.
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