Answer:

Explanation:
Hello,
Based on the information and the units of the given data, the integrated rate law turns out into:

Best regards.

.
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Note : Because Many of My Dreams came true and I realized.
Answer: B.
Explanation:
Trust me already took the quiz on it its B.
Answer:

Explanation:
Hello there!
In this case, according to the given information, it will be possible for us to use the Dalton's law, in order to solve this problem. However, we first need to calculate the mole fraction of oxygen by firstly calculating the moles of each gas:

Next, we calculate such mole fraction as follows:

Then, given the following equation:

So we solve for the total pressure as follows:

Regards!
Under STP condition, the gas has a rule of 22.4 L per mole. And according to the ideal gas law, V1/T1=V2/T2. Under STP, 1.5 mol gas has volume of 33.6 L. So the volume under 22 C is 33.6*295/273=36.3 L.