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SSSSS [86.1K]
3 years ago
6

What is in the solar system?

Chemistry
2 answers:
Zina [86]3 years ago
7 0

Answer:

All of the above

Explanation:

All of this is in the solar system.

Marina86 [1]3 years ago
3 0

Answer:

all of the above

Explanation:

all of this is in the solar system

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1. Determine the number of significant figures in the following values:
denpristay [2]

Answer:

The zero to the left of a decimal value less than 1 is not significant.All trailing zeros that are placeholders are not significant.Zeros between non-zero numbers are significant.All non-zero numbers are significant.

7 0
2 years ago
Why is the melting point of a network solid so high? How is this related to what a network solid is?
Alexxandr [17]
I believe that the answer to the question provided above is that molecules in solid are compact and are connected. It requires huge energy to move it, thus requires high temperature.
Hope my answer would be a great help for you.    If you have more questions feel free to ask here at Brainly.
4 0
3 years ago
The Ka of hydrazoic acid (HN3) is 1.9 × 10-5 at 25.0 °C. What is the pH of a 0.40 M aqueous solution of HN3?
siniylev [52]

Answer:

The pH of the solution is 2.56.

Explanation:

Given :

Concentration (c) = 0.40 M

Acid dissociation constant = K_a=1.9\times 10^{-5}

The equilibrium reaction for dissociation of HN_3 (weak acid) is,

                           HN_3+H_2O\rightleftharpoons N_3^{-}+H_3O^+

initially conc.         c                       0         0

At eqm.              c(1-\alpha)                c\alpha        c\alpha

Dissociation constant is given as:

K_a=\frac{(c\alpha)(c\alpha)}{c(1-\alpha)}

1.9\times 10^{-5}=\frac{(0.40\alpha)(0.40\alpha)}{0.40(1-\alpha)}

By solving the terms, we get value of (\alpha)}

\alpha=0.00686832

No we have to calculate the concentration of hydronium ion or hydrogen ion.

[H^+]=c\alpha=0.4\times 0.00686832=0.002747 M

Now we have to calculate the pH.

pH=-\log [H^+]

pH=-\log (0.002747)

pH=2.56

Therefore, the pH of the solution is, 2.56.

8 0
4 years ago
If the decomposition of a sample of KClO3 produces 3.29 g of O2 , what was the mass (g) of the original sample?
zalisa [80]

Answer: Thus 8.41 g was the mass of the original sample

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}

\text{Moles of} O_2=\frac{3.29g}{32g/mol}=0.103moles

2KClO_3\rightarrow 2KCl+3O_2  

According to stoichiometry :

As 3 moles of O_2 are produced by = 2 moles of KClO_3

Thus 0.103 moles of O_2 are produced by =\frac{2}{3}\times 0.103=0.0687moles  of KClO_3

Mass of KClO_3=moles\times {\text {Molar mass}}=0.0687moles\times 122.5g/mol=8.41g

Thus 8.41 g was the mass of the original sample.

3 0
3 years ago
What is the number of moles of NaOH in 16.5 mL of 0.750 Molar NaOH?
Alchen [17]

Answer:

0.0165 (L) * 0.750 (mol/L) = 0.0124 mol NaOH in 16.5 mL

Explanation:

5 0
3 years ago
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