Question:
A particle moving along the x-axis has a position given by x=(24t - 2.0t³)m, where t is measured in s. What is the magnitude of the acceleration of the particle at the instant when its velocity is zero
Answer:
24 m/s
Explanation:
Given:
x=(24t - 2.0t³)m
First find velocity function v(t):
v(t) = ẋ(t) = 24 - 2*3t²
v(t) = ẋ(t) = 24 - 6t²
Find the acceleration function a(t):
a(t) = Ẍ(t) = V(t) = -6*2t
a(t) = Ẍ(t) = V(t) = -12t
At acceleration = 0, take time as T in velocity function.
0 =v(T) = 24 - 6T²
Solve for T
Substitute -2 for t in acceleration function:
a(t) = a(T) = a(-2) = -12(-2) = 24 m/s
Acceleration = 24m/s
Answer:
Series
Explanation:
Because I listen to my science teacher
Well you know the formula is,
Power= Work/Time
So as time increases, Power Decreases, it's an inverse relationship.
Think about it like this, to have more "power" you have to be able to do a lot in a short amount of time, so by spending more time on something, your power decreases.
It would be gravity i do beileve
Answer:
0.21 lunar month
Explanation:
the radius of moon = r₁
time period of the moon = T₁ = 1 lunar month
The radius of the satellite = 0.35 r₁
Time period of satellite
The relation between time period and radius
now,
T₂ = 0.21 lunar month
hence, the time period of revolution of satellite is equal to 0.21 lunar month
