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alina1380 [7]
3 years ago
14

С

Physics
1 answer:
Lelechka [254]3 years ago
8 0

Answer:

a = 0.8 [m/s²]

Explanation:

To solve this problem we must use Newton's second law which tells us that the resulting force on a body is equal to the product of mass by acceleration, in this way we come to the following equation:

∑F = m*a

where:

F = forces applied [N]

m = mass = 1000 [kg]

a = acceleration [m/s²]

Now using Newton's second law.

1200 - 400 = 1000*a\\800 = 1000 *a\\a=0.8[m/s^{2} ]

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Answer:

Explanation:

Given

mass of cannon and cart is m_1=6475.91 kg

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mass of Projectile m_2=234 kg

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Launch angle \theta =31.3^{\circ}

As the External Force is zero therefore we can conserve momentum

Initially both Projectile and cannon is at rest

Conserving momentum in horizontal direction

m_1u_1+m_2u_2=m_1v_1+m_2v_2\cos 31.3

0+0=6475.91\times v_1+234\times 170\cdot \cos (31.3)

v_1=-\frac{234\times 170\cdot \cos (31.3)}{6475.91}

v_1=-5.24 m/s

i.e. cannon is moving in opposite direction of Projectile

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