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mylen [45]
3 years ago
9

I am so confused! Can anyone help me with this trig problem?

Mathematics
1 answer:
Dominik [7]3 years ago
4 0

\frac{5\pi }{4} or \frac{7\pi }{4}

divide both sides by 2

sinΘ = - \frac{\sqrt{2} }{2}

Since the sin ratio is negative then Θ is in third / fourth quadrants

Θ = sin^{- 1} (\frac{\sqrt{2} }{2}) = \frac{\pi }{4} related acute angle

Θ = ( π + \frac{\pi }{4} ) = \frac{5\pi }{4}

or Θ = ( 2π - \frac{\pi }{4} ) = \frac{7\pi }{4}




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The image T' =  (\frac{2}{3}(-1)+\frac{1}{3} , \frac{2}{3}(-2)-\frac{1}{3} ) or

(\frac{-2}{3}+\frac{1}{3} , \frac{-4}{3}-\frac{1}{3} )

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Now, label the image of RST on the graph as shown below in the attachment:

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