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2 years ago

I am so confused! Can anyone help me with this trig problem?

Mathematics

1 answer:

Dominik [7]2 years ago

4 0

$\frac{5\pi }{4}$ or $\frac{7\pi }{4}$

divide both sides by 2

sinΘ = - $\frac{\sqrt{2} }{2}$

Since the sin ratio is negative then Θ is in third / fourth quadrants

Θ = $sin^{- 1}$ ( $\frac{\sqrt{2} }{2}$ ) = $\frac{\pi }{4}$ related acute angle

Θ = ( π + $\frac{\pi }{4}$ ) = $\frac{5\pi }{4}$

or Θ = ( 2π - $\frac{\pi }{4}$ ) = $\frac{7\pi }{4}$

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3 years ago

Gary is 8 years older than his brother. Six years ago Gary was three times as old as his brother. How old are they now?

Yuliya22 [10]

Answer:Gary-18 years brother-10 years

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3 years ago

x = c1 cos(t) + c2 sin(t) is a two-parameter family of solutions of the second-order DE x'' + x = 0. Find a solution of the seco

igomit [66]

Answer:

$x=-cos(t)+2sin(t)$

Step-by-step explanation:

The problem is very simple, since they give us the solution from the start. However I will show you how they came to that solution:

A differential equation of the form:

$a_n y^n +a_n_-_1y^{n-1}+...+a_1y'+a_oy=0$

Will have a characteristic equation of the form:

$a_n r^n +a_n_-_1r^{n-1}+...+a_1r+a_o=0$

Where solutions $r_1,r_2...,r_n$ are the roots from which the general solution can be found.

For real roots the solution is given by:

$y(t)=c_1e^{r_1t} +c_2e^{r_2t}$

For real repeated roots the solution is given by:

$y(t)=c_1e^{rt} +c_2te^{rt}$

For complex roots the solution is given by:

$y(t)=c_1e^{\lambda t} cos(\mu t)+c_2e^{\lambda t} sin(\mu t)$

Where:

$r_1_,_2=\lambda \pm \mu i$

Let's find the solution for $x''+x=0$ using the previous information:

The characteristic equation is:

$r^{2} +1=0$

So, the roots are given by:

$r_1_,_2=0\pm \sqrt{-1} =\pm i$

Therefore, the solution is:

$x(t)=c_1cos(t)+c_2sin(t)$

As you can see, is the same solution provided by the problem.

Moving on, let's find the derivative of $x(t)$ in order to find the constants $c_1$ and $c_2$ :

$x'(t)=-c_1sin(t)+c_2cos(t)$

Evaluating the initial conditions:

$x(0)=-1\\\\-1=c_1cos(0)+c_2sin(0)\\\\-1=c_1$

And

$x'(0)=2\\\\2=-c_1sin(0)+c_2cos(0)\\\\2=c_2$

Now we have found the value of the constants, the solution of the second-order IVP is:

$x=-cos(t)+2sin(t)$

3 0

2 years ago

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First find the amount of each payment:
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The percentage is the service charge divided by total cost:
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2 years ago

Find the value of 14×2+8÷4

dalvyx [7]

Answer:

14X2+8÷4 equals 30...........

4 0

3 years ago

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