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3 years ago

13

#5 please help me thank you.

2 answers:

saul85 [17]3 years ago

8 0

Area = length * width
Area = (n yds + 40 yds) * 30 yds

or
Area = (30 yds * n yards) + (30 yds * 40 yards)
This is if you add the area of the rides to the area of the arcade (the first parenthesis is the rides, the second is the arcade.)

Fittoniya [83]3 years ago

5 0

Cant see problem at all

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Artyom0805 [142]

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3 years ago

a fishbowl shaped like a sphere is filled with water. The fishbowl has a diameter of 16 inches. Which measurement is closest to

gregori [183]

Answer:

The volume of the water in the fishbowl is equal to

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Step-by-step explanation:

we know that

The volume of the sphere (a fishbowl) is equal to

$V=\frac{4}{3}\pi r^{3}$

In this problem we have

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substitute

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convert to mixed number

$\frac{2,048}{3}\pi\ in^{3}=\pi (\frac{2,046}{3}+\frac{2}{3})=(682\frac{2}{3})\pi\ in^{3}$

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3 years ago

Read 2 more answers

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stiks02 [169]

Answer:

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2 years ago

Adam is building a rectanglar swimming pool. The perimeter of the pool must be no more then 120 feet. If the length of the pool

jasenka [17]

Answer:

$W\leq 38\ ft$

The maximum width must be $38\ ft$

Step-by-step explanation:

Let

L ----> the length of the rectangular pool

W ---> The width of the rectangular pool

we know that

$P\leq 120\ ft$

$P=2(L+W)$

so

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we have

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substitute the value of L in the inequality A

$2(W+22)\leq 120$

simplify

$(W+22)\leq 60$

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The maximum width must be $38\ ft$

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3 years ago

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lisov135 [29]

Answer:

D) 22/7

Step-by-step explanation:

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3 years ago