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Rudiy27
3 years ago
6

Question 8, thanks guys

Mathematics
2 answers:
NISA [10]3 years ago
6 0
The answer is B, each interval goes up by 12 so the incline would be, 12,24,36,48,60
Natasha2012 [34]3 years ago
5 0

Answer:

B.

Step-by-step explanation:

Use the multiplication table of 12 and find that 5x12=60. Answer B is the only one that has that.

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Help please<br>Mark as brainliest
34kurt
You need to use this formula:
([a]/[sinA])=([c]/[sinC])-I am going to use 'a' for the x, and 'c' for 16(square root of 3)
Now its just getting 'a' by itself.
([c] times [sinA])/([sinC])=[a]
[c]=16 square root of 3
sinA=sin(60)=(square root of 3)/2
sinC=sin(90)=1

Plug it in to get 24 for a, or x. Do the same to figure out y with the new sides.
The final y is:
8 square root of 3
Final answer is C.
8 0
3 years ago
If a#b = a+2b, for integers a and b, what is the value of 3#4?
STatiana [176]
Can u translate to indonesia please.
8 0
3 years ago
Micah is twice as old as Richard. Richard is three times as old as Ken. Ken is six years old. How old is Micah?
iVinArrow [24]

Answer:

36

Step-by-step explanation:

Ken = 6 yo

6 *3 = 18

Richard = 18 yo

8 * 2 = 36

Micah = 36

7 0
3 years ago
Solve for y. -3/y=6 Simplify your answer as much as possible.
Molodets [167]
Solving for "y" means that we need to get y to be on one side of the equation. It should look like y= something. To get the y by itself, we need to get rid of that -3. To do that, we'll have to divide by -3 (because even though there's a y being divided, the -3 is still the numerator). 6/-3 is -1/2. Therefore your answer is y=-1/2

<em>Don't forget to rate this answer the Brainliest!</em>
7 0
3 years ago
Find the equation of the line passing through(1,2) and making an angle of 30 degree with y intercept
olya-2409 [2.1K]

Answer:

Equation of the straight line passing through the point ( 1,2 ) and having the slope

 x - √3y -1+2√3 =0

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that the point (1,2) and an angle = ∝ = 30°

The slope of the line

             m = tan 30°

             m = \frac{1}{\sqrt{3} } }

<u><em>Step(ii)</em></u>:-

Equation of the straight line passing through the point ( 1,2 ) and having the slope

 m = \frac{1}{\sqrt{3} } }

           y - y₁ = m(x-x₁)

          y - 2 = \frac{1}{\sqrt{3} } } ( x -1)

        √3(y-2) = (x-1)

⇒       √3y - 2√3 = x -1

           x - √3y -1+2√3 =0

   

4 0
3 years ago
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