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Kamila [148]
3 years ago
5

Need help ASAP!!!!!!!

Chemistry
1 answer:
geniusboy [140]3 years ago
8 0
My Heroes is the time of my time I am in college now that I will do it again tomorrow night and you can do something to me about it and then I will never go back again I hope that I can do this again I don’t want
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PLEASE HELP
nata0808 [166]

Answer:

Is this math? Cause as a fourth grader, I can do Algebra, but not this.

Explanation:

7 0
2 years ago
The two different types of color are primary light colors and primary pigment colors. True or false
Nonamiya [84]
Your answer would be True
7 0
3 years ago
True/False: When a substance is heated, the change in energy causes the bonds between particles to become stronger.​
Rzqust [24]

Answer:

false

Explanation:

the energy causes the bonds to become looser

5 0
3 years ago
Read 2 more answers
A 2.0 molal sugar solution has approximately the same freezing point as 1.0 molal solution of 1) CaCl2 2) CH3COOH 3) NaCl 4) C2H
sertanlavr [38]

Answer:

3) NaCl.

Explanation:

<em>∵ ΔTf = iKf.m</em>

where, <em>i</em> is the van 't Hoff factor.

<em>Kf </em>is the molal depression freezing constant.

<em>m</em> is the molality of the solute.

<em>The van 't Hoff factor is the ratio between the actual concentration of particles produced when the substance is dissolved and the concentration of a substance as calculated from its mass. </em>

<em></em>

  • For most non-electrolytes dissolved in water, the van 't Hoff factor is essentially 1.

<em>So, for sugar: i = 1.</em>

<em>∴ ΔTf for sugar = iKf.m = (1)(Kf)(2.0 m) = 2 Kf.</em>

<em></em>

  • For most ionic compounds dissolved in water, the van 't Hoff factor is equal to the number of discrete ions in a formula unit of the substance.

For NaCl, it is electrolyte compound which dissociates to Na⁺ and Cl⁻.

<em>So, i for NaCl = 2.</em>

<em>∴ ΔTf for NaCl = iKf.m = (2)(Kf)(1.0 m) = 2 Kf.</em>

<em></em>

<em>So, the right choice is: 3) NaCl.</em>

<em></em>

8 0
3 years ago
If I have 2 liters of gas held at a pressure of 78 atm and a temperature of 900 k, what will be the volume of the gas if I decre
dangina [55]

Answer:

V2 = 2.88L

Explanation:

P1= 78atm, V1= 2L, T1= 900K, P2= 45atm, V2=? T2= 750K

Applying the general gas equation

P1V1/T1 = P2V2/T2

Substitute the above

(78*2)/900= (45*V2)/750

V2= (78*2×750)/(900*45)

V2= 2.88L

7 0
3 years ago
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