<u>Answer:</u> The mass of sample A after given time is 99.05 g.
<u>Explanation:</u>
All the radioactive reactions follows first order kinetics.
The equation used to calculate half life for first order kinetics:
We are given:
Putting values in above equation, we get:
Rate law expression for first order kinetics is given by the equation:
where,
k = rate constant =
t = time taken for decay process = 84.2 s
= initial amount of the reactant = 250 g
[A] = amount left after decay process = ?
Putting values in above equation, we get:
Hence, the mass of sample A after given time is 99.05 g.
Answer:
Q4. 2H₂ + O₂ ⟶ 2H₂O; 5; 2
Q5. 24; 30; H₂; 0; 5
Explanation:
Q4.
The equation for the reaction is
2H₂ + O₂ ⟶ 2H₂O
One O₂ molecule reacts with 2H₂ molecules.
We started with seven oxygen molecules. Five of them reacted, so
Two O₂ molecules did not react.
Q5.
Two water molecules form from two hydrogen molecules.
Two water molecules form from one oxygen molecule
Hydrogen forms fewer water molecules of water, so
Hydrogen is the limiting reactant.
The 24 hydrogen molecules will be completely used up.
The number of hydrogen molecules remaining at the end of the reaction is zero.
They have reacted with 12 O₂ molecules.
The number of O₂ molecules remaining is 17 - 12 = 5
It is called as phosphoric acid
Answer:
the answe is 40.3775 L
Explanation:
from boyles law for ideal gas,
we know,
Pressure(P)*Volume(V)= Constant [provided Temperature and the mass is uniform]
then
............1
now, P1= 1.55 atm
V1=52.1 L
P2=2 atm
V2=?
we can find the value of V2 or changed volume of the gas by the help of equation 1.
And the answe is 40.3775 L.
I think it's N and O because on the left 3 times 2 gives you O6 on the left but O3 on the right. Then on the right 1×2= N2 but on the right it's just N1