The atomic number of oxygen is 8 which indicates that there are 8

How many grams of solid iron will be produced from 32.1 grams of iron (III) oxide? Hint: Balance the equation first

Taya2010 [7]

Answer:

22.45g of Fe will be produced

Explanation:

The balanced reaction is:

Fe₂O₃(s) + 3CO(g) → 2Fe(s) + 3CO₂(g)

<em>Where 1 mole of Iron (III) oxide reacts with 2 moles of Iron</em>

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To solve this question we have to find the moles of iron (III) oxide. With these moles and the balanced reaction we can find the moles of iron produced and its mass:

<em>Moles iron (III) oxide -Molar mass: 159.69g/mol-</em>

32.1g Fe₂O₃ * (1mol / 159.69g) = 0.201 moles Fe₂O₃

<em>Moles Iron:</em>

0.201 moles Fe₂O₃ * (2mol Fe / 1mol Fe₂O₃) = 0.402 moles of Fe

<em>Mass Fe -Molar mass: 55.845g/mol-</em>

0.402 moles of Fe * (55.845g/mol) =

<h3>22.45g of Fe will be produced</h3>

3 0

3 years ago

In the temperature part of the experiment, which antacid tablet dissolved the fastest? Which antacid tablet dissolved the slowes

Degger [83]

Answer:

Correct answer is: "Cold Water"

Explanation:

EDGE 2020

8 0

3 years ago

Monosodium glutamate (msg) in soup, iodine in table salt, and beet extract in strawberry ice cream are all examples of

Ghella [55]

Monosodium glutamate (msg) in soup, iodine in table salt, and beet extract in strawberry ice cream are all examples of additives.

Food additives are substances that are usually added to enhance the flavor, appearance or stability of packaged/non-packaged foods. They can be derived from plant or animal sources or synthetically produced. These additives usually undergo safety assessments by the World health Organization (WHO) before it is approved for consumption.

8 0

3 years ago

Use the drop-down menus to identify the class of compounds to which each structure belongs.

inna [77]

Answer:

1) carboxylic acid

2) ether

3) alkyl halide

4) amine

Explanation:

Just took the quiz

3 0

3 years ago

An unknown compound contains only carbon, hydrogen, and oxygen (CxHyOz). Combustion of 6.50 g of this compound produced 9.53 g o

OverLord2011 [107]

Answer:

There were 0.216 moles of oxygen in the sample

Explanation:

Step 1: Data given

Mass of compound = 6.50 grams

Mass of CO2 = 9.53 grams

Molar mass of CO2 = 44.01 g/mol

Mass of H2O = 3.90 grams

Molar mass H2O = 18.02 g/mol

Step 2: Calculate moles CO2

Moles CO2 = 9.53 grams / 44.01 g/mol

Moles CO2 = 0.217 moles

Step 3: Calculate moles C

For 1 mol CO2 we have 1 mol C

For 0.217 moles CO2 we have 0.217 moles C

Step 4: Calculate mass C

Mass C = 0.217 moles C *12.01 g/mol

Mass C = 2.61 grams

Step 5: calculate moles H2O

Moles H2O = 3.90 grams / 18.02 g/mol

Moles H2O = 0.216 moles

Step 6: Calculate moles H

In 1 mol H2O we have 2 moles H

In 0.216 moles H2O we have 0.433 moles H

Step 7: Calculate mass H

Mass H = 0.433 moles * 1.01 g/mol

Mass H = 0.437 grams

Step 8: Calculate mass O

Mass O = 6.50 grams - 2.61 grams - 0.437 grams

Mass O = 3.453 grams

Step 9: Calculate moles O

Moles O = 3.453 grams / 16.0 g/mol

Moles O = 0.216 moles

There were 0.216 moles of oxygen in the sample

4 0

3 years ago