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3 years ago

Someone help What are the products in a chemical reaction?

Chemistry

2 answers:

Alisiya [41]3 years ago

7 0

Answer:

The substances that result from a chemical reaction.

Explanation:

The substances produced at the end of the reaction are known as the products.

Keith_Richards [23]3 years ago

3 0

Answer:

D) The substances that result in a chemical reaction.

In a chemical reaction the substances which takes part in it is called reactant and the result obtained is called product.

Catalyst are the substances which helps in increasing the chemical reaction

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Anna [14]

Answer:

No hoblo englas

Explanation:

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2 years ago

A rigid tank contains 0.66 mol of oxygen (O2). Find the mass of oxygen that must be withdrawn from the tank to lower the pressur

dsp73

Answer:

12.8 g of $O_{2}$ must be withdrawn from tank

Explanation:

Let's assume $O_{2}$ gas inside tank behaves ideally.

According to ideal gas equation- $PV=nRT$

where P is pressure of $O_{2}$ , V is volume of $O_{2}$ , n is number of moles of $O_{2}$ , R is gas constant and T is temperature in kelvin scale.

We can also write, $\frac{V}{RT}=\frac{n}{P}$

Here V, T and R are constants.

So, $\frac{n}{P}$ ratio will also be constant before and after removal of $O_{2}$ from tank

Hence, $\frac{n_{before}}{P_{before}}=\frac{n_{after}}{P_{after}}$

Here, $\frac{n_{before}}{P_{before}}=\frac{0.66mol}{43atm}$ and $P_{after}=17atm$

So, $n_{after}=\frac{n_{before}}{P_{before}}\times P_{after}=\frac{0.66mol}{43atm}\times 17atm=0.26mol$

So, moles of $O_{2}$ must be withdrawn = (0.66 - 0.26) mol = 0.40 mol

Molar mass of $O_{2}$ = 32 g/mol

So, mass of $O_{2}$ must be withdrawn = $(32\times 0.40)g=12.8g$

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2 years ago

Find the density of Liquid A: Liquid A: Mass-138g Volume – 100 mL.

nlexa [21]

Answer:

The answer is

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question

mass of liquid = 138 g

volume = 100 mL

The density of the liquid is

$density = \frac{138}{100} = \frac{69}{5 0}$

We have the final answer as

Hope this helps you

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2 years ago

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2 years ago

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What dont u understand about lewis dot structures???.
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2 years ago