Which energy transformation occurs when an

In this experiment, you were asked to calculate your percent yield of alum assuming that you started with pure aluminum. Actuall

neonofarm [45]

Answer:

Percent yield of alum is 38.6%

Explanation:

Find attached calculations for detailed explanation.

3 0

3 years ago

Liquid hexane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 6.9 g of hexane is mi

MrRa [10]

Answer:

There, there are no leftover for C6H14 instead, an additional mass of 4g of C6H14 is needed to completely react with 38.4g of O2.

Explanation:

Step 1:

We'll begin by writing the balanced equation for the reaction. This is shown below:

2C6H14 + 19O2 —> 12CO2 + 14H2O

Step 2:

Let us calculate the masses of C6H14 and O2 that reacted from the balanced equation. This is illustrated below:

2C6H14 + 19O2 —> 12CO2 + 14H2O

Molar Mass of C6H14 = (12x6) + (14x1) = 72 + 14 = 86g/mol

Mass of C6H14 from the balanced equation = 2 x 86 = 172g

Molar Mass of O2 = 16x2 =32g/mol

Mass of O2 from the balanced equation = 19 x 32 = 608g

From the balanced equation above, 172g of C6H14 reacted with 608g of O2.

Step 3.

Now, let us determine the mass of C6H14 that will react with 38.4 g of oxygen. This is illustrated below:

From the balanced equation above, 172g of C6H14 reacted with 608g of O2.

Therefore, Xg of C6H14 will react with 38.4g of O2 i.e

Xg of C6H14 = (172 x 38.4) /608

Xg of C6H14 = 10.9g

From the calculations made above, we can see clearly that the mass of C6H14 is limited as the reaction requires 10.9g of C6H14 and only 6.9g was given. There, there are no leftover for C6H14 instead, an additional mass ( 10.9 - 6.9 = 4g) of 4g of C6H14 is needed to completely react with 38.4g of O2.

5 0

3 years ago

The town of Eatonville has decided to replace all of the incandescent light bulbs in their public buildings with more energy-eff

astraxan [27]

Answer:A

Explanation:becuse they waste less heat energy

6 0

2 years ago

Problem PageQuestion Methane gas and chlorine gas react to form hydrogen chloride gas and carbon tetrachloride gas. What volume

IgorC [24]

Methane gas and chlorine gas react to form hydrogen chloride gas and carbon tetrachloride gas. What volume of hydrogen chloride would be produced by this reaction if 3.16 L of chlorine were consumed at STP.

Be sure your answer has the correct number of significant digits.

Answer: Thus volume of carbon tetrachloride that would be produced is 0.788 L

Explanation:

According to ideal gas equation:

$PV=nRT$

P = pressure of gas = 1 atm (at STP)

V = Volume of gas = 3.16 L

n = number of moles = ?

R = gas constant = $0.0821Latm/Kmol$

T =temperature = $273K=$

$n=\frac{PV}{RT}$

$n=\frac{1atm\times 3.16L}{0.0820 L atm/K mol\times 273K}=0.141moles$

$CH_4+4Cl_2\rightarrow 4HCl+CCl_4$

According to stoichiometry:

4 moles of chlorine produces = 1 mole of carbon tetrachloride

Thus 0.141 moles of methane produces = $\frac{1}{4}\times 0.141=0.0352$ moles of carbon tetrachloride

volume of carbon tetrachloride = $moles\times {\text {Molar volume}}=0.0352mol\times 22.4L/mol=0.788L$

Thus volume of carbon tetrachloride that would be produced is 0.788 L

8 0

3 years ago

When sodium bicarbonate and acetic acid are combined in a beaker and allowed to

777dan777 [17]

Answer: C excess reactant

Reason: It is not catalyst because catalyst are not consumed. It is not product because it was one of the reactants. It is not limiting because there was excess left over.

8 0

3 years ago

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