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3 years ago

3. Consider the function y = x^2 + 4x – 4.

Mathematics

1 answer:

jeka57 [31]3 years ago

6 0

Answer:

a) (-2,-8)

b) not sure :(

c) (0,-4)

Step-by-step explanation:

To find the vertex rewrite in vertex form and use this form to find the vertex (h,k). To find the y-intercept, substitute in 0 for x and solve for y.

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How much money, in dollars, is available on his card after he takes 0 rides?

snow_tiger [21]

Answer:

However much he had on his card in the first place.

Step-by-step explanation:

Say he had $500 on his card. He took 0 rides ( no rides ) so he doesn't lose any money. Leaving him with his starting amount, $500.

8 0

2 years ago

the graph shows two functions, f(x) and g(x). if the functions are combined so that h(x) = f(x) - g(x), then the domain of the f

Sergio039 [100]

The domain of the function h(x) is x is greater than -1

<h3>How to determine the domain of the function h(x)?</h3>

The graphs of the functions are given as attachment

From the attachment, we have the following domains:

Domain of f(x): x > 2
Domain of g(x): x > -1

The equation of function h(x) is

h(x) = f(x) - g(x)

The domain of the function g(x) is greater than that of the function f(x)

This means that the function h(x) will assume that domain of the function g(x)

Hence, the domain of the function h(x) is x is greater than -1

Read more about domain at:

brainly.com/question/1770447

#SPJ1

5 0

1 year ago

Simplify: (3 × 22) ÷ 6 + [28 – (4)2] Question 17 options: A) 32 B) 23 C) 46 D) 55

algol13

Answer:

Step-by-step explanation:

Here the trick is to perform the indicated operations in the correct order. Anything inside parentheses must be done first, followed by any multiplication or division, followed by any addition or subtraction.

Doing the work inside parentheses first:

(3 × 22) ÷ 6 + [28 – (4)2] => (66) ÷ 6 + [28 - 8], or

(66) ÷ 6 + [28 - 8] => 11 + [20], or 31

3 0

3 years ago

Find the equation of ellipse passing throgh (1,4) and (-3,2)

irinina [24]

Answer:

$\displaystyle \frac{ {3x}^{2} }{ 35 } + \frac{{2y}^{2} }{ 35 } = 1$

Step-by-step explanation:

we want to figure out the ellipse equation which passes through (1,4) and (-3,2)

the standard form of ellipse equation is given by:

$\displaystyle \frac{(x - h {)}^{2} }{ {a}^{2} } + \frac{(y - k {)}^{2} }{ {b}^{2} } = 1$

where:

(h,k) is the centre
a is the horizontal redius
b is the vertical radius

since the centre of the equation is not mentioned, we'd assume it (0,0) therefore our equation will be:

$\displaystyle \frac{ {x}^{2} }{ {a}^{2} } + \frac{{y}^{2} }{ {b}^{2} } = 1$

substituting the value of x and y from the point (1,4),we'd acquire:

$\displaystyle \frac{ 1}{ {a}^{2} } + \frac{16}{ {b}^{2} } = 1$

similarly using the point (-3,2), we'd obtain:

$\displaystyle \frac{ 9}{ {a}^{2} } + \frac{4 }{ {b}^{2} } = 1$

let 1/a² and 1/b² be q and p respectively and transform the equation:

$\displaystyle \begin{cases} q + 16p = 1 \\ 9q + 4p = 1 \end{cases}$

solving the system of linear equation will yield:

$\displaystyle \begin{cases} q = \dfrac{3}{35} \\ \\ p = \dfrac{2}{35} \end{cases}$

substitute back:

$\displaystyle \begin{cases} \dfrac{1}{ {a}^{2} } = \dfrac{3}{35} \\ \\ \dfrac{1}{ {b}^{2} } = \dfrac{2}{35} \end{cases}$

divide both equation by 1 which yields:

$\displaystyle \begin{cases} {a}^{2} = \dfrac{35}{ 3} \\ \\ {b}^{2} = \dfrac{35}{2} \end{cases}$

substitute the value of a² and b² in the ellipse equation , thus:

$\displaystyle \frac{ {x}^{2} }{ \dfrac{35}{3} } + \frac{{y}^{2} }{ \dfrac{35}{2} } = 1$

simplify complex fraction:

$\displaystyle \frac{ {3x}^{2} }{ 35 } + \frac{{2y}^{2} }{ 35 } = 1$

and we're done!

(refer the attachment as well)

8 0

3 years ago

Find the congruent line segments

mash [69]

AB and EF
BC and FD
AC and ED

4 0

3 years ago