d = distance between the two cities
v₁ = average speed while going from chicago to kansas city = 440 knots
t₁ = time taken to travel distance going from chicago to kansas city
time taken to travel distance going from chicago to kansas city is given as
t₁ = d/v₁
t₁ = d/440 eq-1
v₂ = average speed while going from kansas city to chicago = 110 knots
t₂ = time taken to travel distance going from kansas city to chicago
time taken to travel distance going from kansas city to chicago is given as
t₂ = d/v₂
t₂ = d/110 eq-2
Given that :
t₂ = t₁ + 3
using eq-1 and eq-2
(d/110) = (d/440) + 3
d = 440
Answer:
(4, 0)
Step-by-step explanation:
given the 2 equations
y = x - 4 → (1)
- 4x - 6y = - 16 → (2)
substitute y = x - 4 into (2)
- 4x - 6(x - 4) = - 16
- 4x - 6x + 24 = - 16
- 10x + 24 = - 16 ( subtract 24 from both sides )
- 10x = - 40 ( divide both sides by - 10 )
x = 4
substitute x = 4 into (1) for corresponding value of y
y = 4 - 4 = 0
solution is (4, 0)
Answer:
y = 1/2x - 7
Step-by-step explanation:
slope intercept form:
y = mx + b
y = -5
m(slope) = 1/2
x = 4
y = mx + b
<em>substitute </em>
-5 = 1/2*4 + b
-5 = 2 + b
-5 - 2 = b
-7 = b
y = 1/2x - 7
Answer: x2 + 12x
Step-by-step explanation:
