Given:
2 Mg + O2 → 2 MgO
So,
<span>(25.0 g of Mg / 24.3051 g/mole) x (1/2) x (22.4 L/mole) = 11.5 L of Oxygen will react with 25 grams of magnesium metal.</span>
<span>Answer – We are given, 2H2+O2 ----> 2H2O , deltaH = -48.4 kJ Moles of H2 =1.8 moles From the above given balanced equation We know, 2 moles of H2 = -48.4 kJ So, 1.8 moles of H2 = ? kJ = 1.8 moles of H2 X -48.4 kJ / 2 moles of H2 =-43.6 kJ So, when 1.8 mol of H2...</span>
Answer:
Yeild of CO2 is approximately 54g
Explanation:
Using reaction stoichiomety and coeeficients, and knowing O2 is limiting reactant, 54 g of CO2 is produced.
