<span> Greenhouse gases were not historically present in the atmosphere.</span>
Hey there!
D = m / V
0.775 = m / 50.0
m = 0.775 * 50.0
m = 38.75 g
1 mol ------------ 6,02×10²³
0,17 mol ------- X
X =(0,17×6,02×10²³)/1
X = 1,0234×10²³ molecules H₂O
:•)
Answer:
71.92 kPa
Explanation:
Using the combined gas law equation;
P1V1/T1 = P2V2/T2
Where;
P1 = initial pressure (kPa)
P2 = final pressure (kPa)
V1 = initial volume (L)
V2 = final volume (L)
T1 = initial temperature (K)
T2 = final temperature (K)
According to the information provided in this question;
T1 = 50°C = 50 + 273 = 323K
V1 = 105L
T2 = -25°C = -25 + 273 = 248K
P2 = 105.4 kPa
P1 = ?
V2 = 55.0 L
Using P1V1/T1 = P2V2/T2
P1 × 105/323 = 105.4 × 55/248
105P1/323 = 5797/248
0.325P1 = 23.375
P1 = 23.375 ÷ 0.325
P1 = 71.92 kPa
NAMJIN!!!!!!!!!!!!!!!!!!!!!!!!!!
