The formula of chalcopyrite is CuFeS₂.
The molar mass of chalcopyrite - 183.5 g/mol
The mass of Cu in 1 mol of chalcopyrite is - 63.5 g
When 183.5 g of chalcopyrite is mined, the mass of Cu obtained - 63.5 g
So if 63.g of Cu is needed mass of chalcopyrite required - 183.5 g
Then to gain 370 g of pure Cu - mass of chalcopyrite needed -183.5/63.5 x 370
therefore mass of chalcopyrite to be mined - 1069.21 g
The one with the largest atomic radius is barium
Hoped this helped:)
Due to energy being a reactant instead of a product, the process is endothermic. The system must absorb a quantity of energy before it can react, so it must be an endothermic system.
The correct answer is 80 atoms of sulfur.
In order to answer this question we must firstly find the molecular formula of tetrasulfur tetranitrogen. The said molecule has the molecular formula of S4N4.
Therefore, each molecule of S4N4 contains four atoms of sulfur (S).
If one molecule of S4N4 contains 4 sulfur atoms, then twenty molecules contain
20 x 4= 80 atoms of sulfur.
