The initial velocity of Ms. Stafford is
, while her acceleration is
This is a uniform accelerated motion, so we can calculate the total distance travelled by Ms. Stafford in a time of
using the law of motion for a uniform accelerated motion:
Answer:
100 times
Explanation:
Question:
The cylinders of a hydraulic part are 15cm and 150cm in diameter. How many times will the force acting on the piston with the smaller diameter be multiplied?
Solution:
Smaller diameter = 15cm
Bigger diameter = 150cm
Using Pascal's principle
F/A = f/a
Pressure = Force/Area
Pressure on piston with bigger diameter = pressure on piston with smaller diameter
Let Pressure on piston with bigger diameter = P
P =F/A
pressure on piston with smaller diameter = p
p = f/a
F/A = f/a
F×a = f×A
F/f = A/a
Area = πr^2
F/f = [π×(150)^2]/ [π×(15)^2]
F/f = (150)^2/ (15)^2
F/f = 100
F = 100f
The force acting on the piston with the smaller diameter will be multiplied 100 times.
Rubber,Plastic,I think thats it but everyone that can float has a high buoyancy
Answer: Speed = 4 m/s
Explanation:
The parameters given are
Mass M = 60 kg
Height h = 0.8 m
Acceleration due to gravity g= 10 m/s2
Before the man jumps, he will be experiencing potential energy at the top of the table.
P.E = mgh
Substitute all the parameters into the formula
P.E = 60 × 9.8 × 0.8
P.E = 470.4 J
As he jumped from the table and hit the ground, the whole P.E will be converted to kinetic energy according to conservative of energy.
When hitting the ground,
K.E = P.E
Where K.E = 1/2mv^2
Substitute m and 470.4 into the formula
470.4 = 1/2 × 60 × V^2
V^2 = 470.4/30
V^2 = 15.68
V = square root (15.68)
V = 3.959 m/s
Therefore, the speed of the man when hitting the ground is approximately 4 m/s
Answer:
d = 18 m
Explanation:
Given that,
The speed of a baseball, v = 36 m/s
We need to find the distance from the mound to home plate if the ball takes 0.5 seconds to leave the pitcher's hand and cross the plate.
Let the distance be d. We can find it using the formula,
Speed = distance/time
or
So, the required distance is equal to 18 m.